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2 years ago

Decrease £843 by 91% rounded to 2 DP

Mathematics

1 answer:

34kurt2 years ago

6 0

Answer:

Percent (%)' means 'out of one hundred':

p% = p 'out of one hundred',

p% is read p 'percent',

p% = p/100 = p ÷ 100.

91% = 91/100 = 91 ÷ 100 = 0.91.

100% = 100/100 = 100 ÷ 100 = 1.

Decrease number by 91% of its value.

Percentage decrease = 91% × 843

New value = 843 - Percentage decrease

Calculate the New Value

New value =

843 - Percentage decrease =

843 - (91% × 843) =

843 - 91% × 843 =

(1 - 91%) × 843 =

(100% - 91%) × 843 =

9% × 843 =

9 ÷ 100 × 843 =

9 × 843 ÷ 100 =

7,587 ÷ 100 =

75.87

Calculate absolute change (actual difference)

Absolute change (actual difference) =

New value - 843 =

75.87 - 843 =

- 767.13

Proof.

Calculate percentage decrease:

Percentage decrease =

91% × 843 =

91 ÷ 100 × 843 =

91 × 843 ÷ 100 =

76,713 ÷ 100 =

767.13

Step-by-step explanation:

Hope it is helpful....

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GenaCL600 [577]

Close off the hemisphere $S$ by attaching to it the disk $D$ of radius 3 centered at the origin in the plane $z=0$ . By the divergence theorem, we have

$\displaystyle\iint_{S\cup D}\vec F(x,y,z)\cdot\mathrm d\vec S=\iiint_R\mathrm{div}\vec F(x,y,z)\,\mathrm dV$

where $R$ is the interior of the joined surfaces $S\cup D$ .

Compute the divergence of $\vec F$ :

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Compute the integral of the divergence over $R$ . Easily done by converting to cylindrical or spherical coordinates. I'll do the latter:

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From this we need to subtract the contribution of

$\displaystyle\iint_D\vec F(x,y,z)\cdot\mathrm d\vec S$

that is, the integral of $\vec F$ over the disk, oriented downward. Since $z=0$ in $D$ , we have

$\vec F(x,y,0)=\dfrac{y^3}3\,\vec\jmath+y^2\,\vec k$

Parameterize $D$ by

$\vec r(u,v)=u\cos v\,\vec\imath+u\sin v\,\vec\jmath$

where $0\le u\le 3$ and $0\le v\le2\pi$ . Take the normal vector to be

$\dfrac{\partial\vec r}{\partial v}\times\dfrac{\partial\vec r}{\partial u}=-u\,\vec k$

Then taking the dot product of $\vec F$ with the normal vector gives

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So the contribution of integrating $\vec F$ over $D$ is

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and the value of the integral we want is

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