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elena-s [515]
3 years ago
11

Decrease £843 by 91% rounded to 2 DP

Mathematics
1 answer:
34kurt3 years ago
6 0

Answer:

Percent (%)' means 'out of one hundred':

p% = p 'out of one hundred',

p% is read p 'percent',

p% = p/100 = p ÷ 100.

91% = 91/100 = 91 ÷ 100 = 0.91.

100% = 100/100 = 100 ÷ 100 = 1.

Decrease number by 91% of its value.

Percentage decrease = 91% × 843

New value = 843 - Percentage decrease

Calculate the New Value

New value =

843 - Percentage decrease =

843 - (91% × 843) =

843 - 91% × 843 =

(1 - 91%) × 843 =

(100% - 91%) × 843 =

9% × 843 =

9 ÷ 100 × 843 =

9 × 843 ÷ 100 =

7,587 ÷ 100 =

75.87

Calculate absolute change (actual difference)

Absolute change (actual difference) =

New value - 843 =

75.87 - 843 =

- 767.13

Proof.

Calculate percentage decrease:

Percentage decrease =

91% × 843 =

91 ÷ 100 × 843 =

91 × 843 ÷ 100 =

76,713 ÷ 100 =

767.13

Step-by-step explanation:

Hope it is helpful....

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Nesterboy [21]

The distance between the two points on the number line is of \mathbf{\frac{5}{9}} units.

-------------------------------------------

  • The distance between two numbers on the number line is given by the <u>subtraction of the greater by the smaller number.</u>
  • The greater number is -\frac{2}{9}
  • The smaller is -\frac{7}{9}.
  • The distance is:

-\frac{2}{9} - (-\frac{7}{9}) = -\frac{2}{9} + \frac{7}{9} = \frac{-2 + 7}{9} = \frac{5}{9}

Thus, distance of \mathbf{\frac{5}{9}} units.

A similar problem is given at brainly.com/question/10795861

8 0
2 years ago
A bag is filled with green and blue marbles. There are 125 marbles in the bag. If there are 29 more green
ValentinkaMS [17]

Answer:

89 green marbles and 46 blue marbles

Step-by-step explanation:

3 0
3 years ago
What is the variable in Samuel is six inches taller than his brother Elijah.if Samuel is 48 inches tall,how tall is Elijah
Taya2010 [7]

Answer: Elijah would be 42 inches tall

Step-by-step explanation:

We all know that Samuel is 48 inches while Elijah is 6 inches shorter.

You subtract 6 from 48 to get 42.

Hopefully, this helped. :D

5 0
3 years ago
(02.02 MC) Triangle ABC is shown. A is at negative 2, 1. B is at negative 1, 4. C is at negative 4, 5. If triangle ABC is reflec
Bezzdna [24]

Given:

The vertices of a triangle ABC are A(-2,1), B(-1,4) and C(-4,5).

Triangle ABC is reflected over the x‐axis, reflected over the y‐axis, and rotated 180 degrees.

To find:

The point B'.

Solution:

If a figure reflected over x-axis, then

(x,y)\to (x,-y)

B(-1,4)\to B_1(-1,-4)

If a figure reflected over y-axis, then

(x,y)\to (-x,y)

B_1(-1,-4)\to B_2(-(-1),-4)

B_1(-1,-4)\to B_2(1,-4)

If a figure rotated 180 degrees about the origin, then

(x,y)\to (-x,-y)

B_2(1,-4)\to B'(-(1),-(-4))

B_2(1,-4)\to B'(-1,4)

So, the coordinate of point B' are (-1,4).

Therefore, the correct option is A.

6 0
3 years ago
At an ocean-side nuclear power plant, seawater is used as part of the cooling system. This raises the temperature of the water t
grandymaker [24]

Answer:

(a1) The probability that temperature increase will be less than 20°C is 0.667.

(a2) The probability that temperature increase will be between 20°C and 22°C is 0.133.

(b) The probability that at any point of time the temperature increase is potentially dangerous is 0.467.

(c) The expected value of the temperature increase is 17.5°C.

Step-by-step explanation:

Let <em>X</em> = temperature increase.

The random variable <em>X</em> follows a continuous Uniform distribution, distributed over the range [10°C, 25°C].

The probability density function of <em>X</em> is:

f(X)=\left \{ {{\frac{1}{25-10}=\frac{1}{15};\ x\in [10, 25]} \atop {0;\ otherwise}} \right.

(a1)

Compute the probability that temperature increase will be less than 20°C as follows:

P(X

Thus, the probability that temperature increase will be less than 20°C is 0.667.

(a2)

Compute the probability that temperature increase will be between 20°C and 22°C as follows:

P(20

Thus, the probability that temperature increase will be between 20°C and 22°C is 0.133.

(b)

Compute the probability that at any point of time the temperature increase is potentially dangerous as follows:

P(X>18)=\int\limits^{25}_{18}{\frac{1}{15}}\, dx\\=\frac{1}{15}\int\limits^{25}_{18}{dx}\,\\=\frac{1}{15}[x]^{25}_{18}=\frac{1}{15}[25-18]=\frac{7}{15}\\=0.467

Thus, the probability that at any point of time the temperature increase is potentially dangerous is 0.467.

(c)

Compute the expected value of the uniform random variable <em>X</em> as follows:

E(X)=\frac{1}{2}[10+25]=\frac{35}{2}=17.5

Thus, the expected value of the temperature increase is 17.5°C.

7 0
3 years ago
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