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4 years ago

Help timed test! At which root does the graph...

Mathematics

1 answer:

Anastaziya [24]4 years ago

5 0

Answer:

x = -2

Step-by-step explanation:

The way you can tell if the graph is going to cross the x-axis or just touch the x-axis is by looking at the power of the factor.

(x - 5)^3 has a power of 3 which is an ODD number. An ODD power means that the graph will cross through the x-axis.

(x + 2)^2 has a power of 2 which is an EVEN number. An EVEN power means that the graph will touch the x-axis.

To find where it will touch the axis set the factor equal to zero and solve.

(x + 2) = 0

subtract 2 from both sides

x = -2

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Leon read 5/7 of the pages in his book.He has 28 pages left to read.How many pages has he read already?

Fittoniya [83]

You would first divide 28 by 7.
28 / 7 = 4.
Now multiply 4 by 5.
4 X 5 = 20.

Therefore, Leon read 20 pages.

4 0

3 years ago

Alex is 12 years older than George. Carl is Three times older than Alex The sum of their ages is 68 Find the ratio of George’s a

earnstyle [38]

Ratio of George’s age to Carl’s age to Alex’s age is 1 : 12 : 4

Solution:

Let "a" be the age of Alex

Let "g" be the age of George

Let "c" be the age of Carl

Alex is 12 years older than George

Therefore,

Age of Alex = 12 + Age of George

a = 12 + g

g = a - 12 ---- eqn 1

Carl is Three times older than Alex

Age of Carl = 3 x Age of Alex

c = 3a -------- eqn 2

The sum of their ages is 68

age of Alex + age of George + age of Carl = 68

a + g + c = 68 ----------- eqn 3

Substitute eqn 1 and eqn 2 in eqn 3

a + a - 12 + 3a = 68

5a - 12 = 68

5a = 12 + 68

5a = 80

a = 16

Substitute a = 16 in eqn 2

c = 3(16) = 48

c = 48

Substitute a = 16 in eqn 1

g = 16 - 12 = 4

g = 4

Find the ratio of George’s age to Carl’s age to Alex’s age

Ratio of George’s age to Carl’s age to Alex’s age = g : c : a

g : c : a = 4 : 48 : 16

Divide the above ratio by 4 to reduce to lowest terms

g : c : a - 1 : 12 : 4

Thus ratio of George’s age to Carl’s age to Alex’s age is 1 : 12 : 4

6 0

3 years ago

A builder purchases 600 bricks for a new residential construction. The dimensions of each brick are 5.1 cm by 10.2 cm by 20.3 cm

Blababa [14]

<h3>Answer:</h3>

1165.83 kg

<h3>Explanation:</h3>

The total mass is the product of volume of one brick, the number of bricks, and the density. For this problem, it is convenient to use dimensions in meters.

$(0.051\,m)(0.102\,m)(0.203\,m)(600)\dfrac{1840\,kg}{m^3}=(0.6336036\,m^3)\dfrac{1840\,kg}{m^3}\\\\=1165.83\,kg$

6 0

4 years ago

Read 2 more answers

3. Factor x2 – 6x – 7. A.(x –7)(x –1) B. (x – 7)(x + 1) C. (x + 7)(x – 1) D. (x + 4)(x + 7)

zhuklara [117]

Its B, because (x-7)(x+1)=x^2-6x-7.

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3 years ago

Can you please explain ME how to solve identity of algebra homework

yKpoI14uk [10]

Step-by-step explanation:

"identity" means an operation that does nothing.

For adding numbers, adding 0 changes nothing, so 0 is the identity for addition.

For multiplication, multiplying by 1 changes nothing, so 1 is the identity for multiplication.

3 0

3 years ago