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4 years ago

Help timed test! At which root does the graph...

Mathematics

1 answer:

Anastaziya [24]4 years ago

5 0

Answer:

x = -2

Step-by-step explanation:

The way you can tell if the graph is going to cross the x-axis or just touch the x-axis is by looking at the power of the factor.

(x - 5)^3 has a power of 3 which is an ODD number. An ODD power means that the graph will cross through the x-axis.

(x + 2)^2 has a power of 2 which is an EVEN number. An EVEN power means that the graph will touch the x-axis.

To find where it will touch the axis set the factor equal to zero and solve.

(x + 2) = 0

subtract 2 from both sides

x = -2

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39x38 multiply using partial prodcuts

yKpoI14uk [10]

39 x 10
= 390

39 x 40 (390 x 4)
= 1,560

39 x 2
= 78

1,560 - 78
= 1,482

ANSWER: 1,482

4 0

3 years ago

A second particle, Q, also moves along the x-axis so that its velocity for 0 £ £t 4 is given by Q t cos 0.063 ( ) t 2 v t( ) = 4

Vladimir79 [104]

Answer:

The time interval when $V_Q(t) \geq 60$ is at $1.866 \leq t \leq 3.519$

The distance is 106.109 m

Step-by-step explanation:

The velocity of the second particle Q moving along the x-axis is :

$V_{Q}(t)=45\sqrt{t} cos(0.063 \ t^2)$

So ; the objective here is to find the time interval and the distance traveled by particle Q during the time interval.

We are also to that :

$V_Q(t) \geq 60$ between $0 \leq t \leq 4$

The schematic free body graphical representation of the above illustration was attached in the file below and the point when $V_Q(t) \geq 60$ is at 4 is obtained in the parabolic curve.

So, $V_Q(t) \geq 60$ is at $1.866 \leq t \leq 3.519$

Taking the integral of the time interval in order to determine the distance; we have:

distance = $\int\limits^{3.519}_{1.866} {V_Q(t)} \, dt$

= $\int\limits^{3.519}_{1.866} {45\sqrt{t} cos(0.063 \ t^2)} \, dt$

= By using the Scientific calculator notation;

distance = 106.109 m

4 0

3 years ago

An optical inspection system is used to distinguish among different part types. The probability of a correct classification of a

Whitepunk [10]

Answer: $\mu=2.88\ \&\ \sigma^2=0.115$

Step-by-step explanation:

Given : The probability of a correct classification of any part is : p=0.96

sample size : n= 3

The formula to find the mean and variance for binomial distribution is given by :-

$\mu=np\\\\\sigma^2=np(1-p)$

Let the random variable X denote the number of parts that are correctly classified.

The, for the given situation, we have

$\mu=3(0.96)=2.88\\\\\sigma^2=(3)(0.96)(1-0.96)=0.1152\approx0.115$

Hence, the mean and variance of X are 2.88 and 0.115 respectively.

4 0

4 years ago

What root means to make or to do

kompoz [17]

"fic" might be the root

3 0

4 years ago

What is a standard form equation of a circle

Gre4nikov [31]

Answer:

360 degrees

Step-by-step explanation:

Its Easy Geometry

7 0

3 years ago