Answer:
The area of the circle = 27.0212cm^2
Step-by-step explanation:
The area for a circle is
A = πr^2
But weve been given the area of the circle in the information provided above
Area of a circle is given as
A = ttr
Where,
A - area of circle
r = radius of the circle
We've been the values of r and tt
r = 8.6cm
tt = 3.142
Inserting the values given into
A = ttr
A = 3.142 * 8.6
A = 27.0212cm^2
The area of the circle is 27.0212cm^2
Answer:
C)
<h3>
log(117.50 / (117.50 - 2050(0.012) ) / log(1+0.012 ) </h3>
Step-by-step explanation:
Formula to calculate compounded monthly payments
A = R( (1-(1+r)^-n) / r)
where
r = 0.14/12
= 0.012
A = 2050
R = 117.50
n =no. of payments
2050 = 117.50 (1 - (1 + 0.012)^-n / 0.012)
cross multiplication
2050 (0.012) / 117.50 = 1 - (1 + 0.012)^-n
1 on other side
(2050 (0.012) / 117.50) - 1 = - (1+0.012)^-n
eliminating minus sign
1 - (2050 (0.012) / 117.50) = (1+0.012)^-n
LCM
(117.50 - 2050(0.012) ) / 117.50 = (1 + 0.012)^-n
power in negative
(117.50 - 2050(0.012) ) / 117.50 = 1 / (1+0.012)^n
reciprocal
117.50 / (117.50 - 2050(0.012) ) = (1+0.012)^n
taking log
log(117.50 / (117.50 - 2050(0.012) ) = log(1+0.012)^n
Answer
log(117.50 / (117.50 - 2050(0.012) ) = n log(1+0.0120)
<h3>
log(117.50 / (117.50 - 2050(0.012) ) / log(1+0.012 ) = n</h3>
Answer:
C = 28.26 in
Step-by-step explanation:
the circumference (C) is calculated as
C = πd ( d is the diameter ) , then
C = 3.14 × 9 = 28.26 in
Answer: A Domain: {-5, 0, 4, 6} Range: {-9,0, 9, 13}
Step-by-step explanation:
Domain is the x-values, least to greatest.
Range is the y-values, least to greatest.
Given:
The expressions are
and
.
To find:
The quotient of
and
expressed in scientific notation.
Solution:
Quotient of
and
is:
![\dfrac{1.888\times 10^9}{5.9\times 10^6}=\dfrac{1.888}{5.9}\times \dfrac{10^9}{10^6}](https://tex.z-dn.net/?f=%5Cdfrac%7B1.888%5Ctimes%2010%5E9%7D%7B5.9%5Ctimes%2010%5E6%7D%3D%5Cdfrac%7B1.888%7D%7B5.9%7D%5Ctimes%20%5Cdfrac%7B10%5E9%7D%7B10%5E6%7D)
![\dfrac{1.888\times 10^9}{5.9\times 10^6}=0.32\times 10^{9-6}](https://tex.z-dn.net/?f=%5Cdfrac%7B1.888%5Ctimes%2010%5E9%7D%7B5.9%5Ctimes%2010%5E6%7D%3D0.32%5Ctimes%2010%5E%7B9-6%7D)
![\dfrac{1.888\times 10^9}{5.9\times 10^6}=0.32\times 10^{3}](https://tex.z-dn.net/?f=%5Cdfrac%7B1.888%5Ctimes%2010%5E9%7D%7B5.9%5Ctimes%2010%5E6%7D%3D0.32%5Ctimes%2010%5E%7B3%7D)
In the scientific notation, the first number is between 1 to 10. So, 0.32 can be written as
.
![\dfrac{1.888\times 10^9}{5.9\times 10^6}=\dfrac{3.2}{10}\times 10^{3}](https://tex.z-dn.net/?f=%5Cdfrac%7B1.888%5Ctimes%2010%5E9%7D%7B5.9%5Ctimes%2010%5E6%7D%3D%5Cdfrac%7B3.2%7D%7B10%7D%5Ctimes%2010%5E%7B3%7D)
![\dfrac{1.888\times 10^9}{5.9\times 10^6}=3.2\times 10^{3-1}](https://tex.z-dn.net/?f=%5Cdfrac%7B1.888%5Ctimes%2010%5E9%7D%7B5.9%5Ctimes%2010%5E6%7D%3D3.2%5Ctimes%2010%5E%7B3-1%7D)
![\dfrac{1.888\times 10^9}{5.9\times 10^6}=3.2\times 10^{2}](https://tex.z-dn.net/?f=%5Cdfrac%7B1.888%5Ctimes%2010%5E9%7D%7B5.9%5Ctimes%2010%5E6%7D%3D3.2%5Ctimes%2010%5E%7B2%7D)
Therefore, the value of the quotient is
.