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Vsevolod [243]
3 years ago
11

Please help will mark BRAINLIEST! This is pt.1

Mathematics
1 answer:
Bad White [126]3 years ago
5 0

Answer:

See below.

Step-by-step explanation:

Problem 1.

1. QU

2. QW

3. UW

Given

4. QUW

Problem 2.

1. CB

2. <1, <2

Given

3. BD, BE

Given

4. ABD, CBE

SAS

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4 hours

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4 years ago
given two terms in a geometric sequence find the 8th term and the recursive formula . a4=-12 and a5=-6
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A geometric sequence is defined by a starting point, a, and a common ratio r

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So, our terms are

\left[\begin{array}{c|c}a_1&a\\a_2&ar\\a_3&ar^2\\a_4&ar^3=-12\\a_5&ar^4=-6\end{array}\right]

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This implies that the common ratio is r = \frac{1}{2}

So, the table becomes

\left[\begin{array}{c|c}a_1&a\\a_2&\frac{1}{2}a\\a_3&\frac{1}{4}a\\a_4&\frac{1}{8}a=-12\\a_5&\frac{1}{16}a=-6\end{array}\right]

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\left[\begin{array}{c|c}a_1&-96\\a_2&-48\\a_3&-24\\a_4&-12\\a_5&-6\\a_6&-3\\\vdots&\vdots\end{array}\right]

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