Hey there!
<h2>Good luck on your assignment and enjoy your day! </h2>
~
This is tricky. Fasten your seat belt. It's going to be a boompy ride.
If it's a 12-hour clock (doesn't show AM or PM), then it has to gain
12 hours in order to appear correct again.
How many times must it gain 3 minutes in order to add up to 12 hours ?
(12 hours) x (60 minutes/hour) / (3 minutes) = 240 times
It has to gain 3 minutes 240 times, in order for the hands to be in the correct positions again. Each of those times takes 1 hour. So the job will be complete in 240 hours = <em>10 days .</em>
Check:
In <u>10</u> days, there are <u>240</u> hours.
The clock gains <u>3</u> minutes every hour ==> <u>720</u> minutes in 240 hours.
In 720 minutes, there are 720/60 = <u>12 hours</u> yay !
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If you are on a military base and your clocks have 24-hour faces,
then at the same rate of gaining, one of them would take 20 days
to appear to be correct again.
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Note:
It doesn't have to be an analog clock. Cheap digital clocks can
gain or lose time too (if they run on a battery and don't reference
their rate to the 60 Hz power that they're plugged into).
TIP:
If you ever need to find the graph of a function, simply plug the function into the desmos graphing calculator! :)
Answer:
Value of the test statistic for this problem = -3.74
Step-by-step explanation:
Here
the sample size n = 1263
and the x = 565
So, the p' -value = 565/1263 = 0.4473
As per the test statistics formula, z value will be evaluated
z = (0.4473-p)/sqrt {p(1-p)/n}
Let us say that p = 0.5
Substituting the given value in above equation, we get -
z = (0.4473-0.5)/sqrt {0.5(1-0.5)/1263}
z = -3.74
