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2 years ago

13

Which property is best used prove a quadrilateral is a rectangle?

1 answer:

vampirchik [111]2 years ago

3 0

Answer:

b

Step-by-step explanation:

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On the coordinate plane below, Point P, is located at (2,-3) and point Q is located at (-4,4). Find the distance between points,

marishachu [46]

Answer:

approximately 9.2195

Step-by-step explanation:

We can use Pythagorean theorem

one leg is 7 and the other leg is 6

square them

49 and 36

add

85

square root

approximately 9.2195

4 0

2 years ago

which one of the following uses estimation to check 267-154=113? a. 300-200=100. b. 113+154=267. c. 300-150=150. d. 270-150=120

Vlada [557]

A. 300-200=100
You round 267 to 300, 154 to 200, and 113 to 100.

8 0

2 years ago

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What is 6 : 8 = n : 12

bonufazy [111]

Answer:

6/8 = n/12

Step-by-step explanation:

hope it helps ;)))))))]))))

6 0

2 years ago

Hello everyone I need some serious help!

vampirchik [111]

Step-by-step explanation:

1/2 the fourth answer :)

5 0

2 years ago

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The line $y = 3$ intersects the graph of $y = 4x^2 + x - 1$ at the points $A$ and $B$. The distance between $A$ and $B$ can be w

raketka [301]

Answer:

61

Step-by-step explanation:

Let's find the points $A$ and $B$ .

We know that the $y$ -coordinates of both are $3$ .

So let's first solve:

$3=4x^2+x-1$

Subtract 3 on both sides:

$0=4x^2+x-1-3$

Simplify:

$0=4x^2+x-4$

I'm going to use the quadratic formula, $x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$ , to solve.

We must first compare to the quadratic equation, $ax^2+bx+c=0$ .

$a=4$

$b=1$

$c=-4$

$\frac{-1 \pm \sqrt{1^2-4(4)(-4)}}{2(4)}$

$\frac{-1 \pm \sqrt{1+64}}{8}$

$\frac{-1 \pm \sqrt{65}}{8}$

Since the distance between the points $A$ and $B$ is horizontal. We know this because they share the same $y-coordinate$ .This means we just need to find the positive difference between the $x$ -values we found for the points of $A$ and $B$ .

So that is, the distance between $A$ and $B$ is:

$\frac{-1+\sqrt{65}}{8}-\frac{-1-\sqrt{65}}{8}$

$\frac{-1+\sqrt{65}+1+\sqrt{65}}{8}$

$\frac{2\sqrt{65}}{8}$

$\frac{\sqrt{65}}{4}$

If we compare this to $\frac{\sqrt{m}}{n}$ , we should see that:

$m=65 \text{ and } n=4$ .

So $m-n=65-4=61$ .

5 0

2 years ago

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