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denis-greek [22]
2 years ago
14

Evaluate.

Mathematics
2 answers:
harina [27]2 years ago
3 0

Answer:

I got .96

Step-by-step explanation:

2+23 is 25. 25 devided by 12 is .48. Times that by 2 and you get . 96. clearly that's not an option though so I'm not sure. sorry. did you make a typo by any chance?

Tems11 [23]2 years ago
3 0

Answer:

bjkoookjnnnnhgfffttgggggggggg

Step-by-step explanation:

hhhhhhhhhhhhhggvg

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Convert 203 yards into meters.
yuradex [85]

Answer:

184.73

Step-by-step explanation:

1 yard = 0.91m

203 yard=?

(203x0.91)/1=184.73.

+1(415) 450-6164

3 0
2 years ago
A simple random sample of 110 analog circuits is obtained at random from an ongoing production process in which 20% of all circu
telo118 [61]

Answer:

64.56% probability that between 17 and 25 circuits in the sample are defective.

Step-by-step explanation:

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

n = 110, p = 0.2

So

\mu = E(X) = np = 110*0.2 = 22

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{110*0.2*0.8} = 4.1952

Probability that between 17 and 25 circuits in the sample are defective.

This is the pvalue of Z when X = 25 subtrated by the pvalue of Z when X = 17. So

X = 25

Z = \frac{X - \mu}{\sigma}

Z = \frac{25 - 22}{4.1952}

Z = 0.715

Z = 0.715 has a pvalue of 0.7626.

X = 17

Z = \frac{X - \mu}{\sigma}

Z = \frac{17 - 22}{4.1952}

Z = -1.19

Z = -1.19 has a pvalue of 0.1170.

0.7626 - 0.1170 = 0.6456

64.56% probability that between 17 and 25 circuits in the sample are defective.

4 0
3 years ago
HELPPPP PLEASEEEEE !!!!!What is the surface area of the composite solid?
Bingel [31]

Answer: answer C is correct or 1,808 meters squared

Step-by-step explanation:

4 0
3 years ago
How to put 17/4 into a mixed number
KiRa [710]
Divide the top by bottom. So 17 divided by 4. Which would be around 4.25
4 0
3 years ago
Read 2 more answers
Greatest percent
cricket20 [7]

Answer:

Percent change from 15 to 18.

 

You need to divide the numbers, but which one goes on top?

 

You know the number increases from 15 to 18, so the percentage must be greater than 100%.

 

The only way to get a number greater than 100% is to put the larger number on top.

 

Therefore, the answer is 18/15 = 1.2

 

Multiply by 100 to get a %

 

1.2 * 100 = 120%

2. Calculate percentage change

from V1 = 5 to V2 = 8

ans= 60%

overall answer gain of 15 yards and 18 yards

8 0
2 years ago
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