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BaLLatris [955]
3 years ago
11

PLS HELPPP FIND X I will mark braniliest

Mathematics
1 answer:
borishaifa [10]3 years ago
8 0

Answer:

x = 11

Step-by-step explanation:

∠ EAB = ∠ AED = 4x ( alternate angles )

∠ AEB and ∠  GEB are adjacent angles on a straight line and sum to 180° , so

∠ AEB + 125° = 180° ( subtract 125° from both sides )

∠ AEB = 55°

The exterior angle of a triangle is equal to the sum of the 2 opposite interior angles.

∠ EBC is an exterior angle of the triangle , then

∠ EBC = ∠ AEB + ∠EAB , that is

9x = 55 + 4x ( subtract 4x from both sides )

5x = 55 ( divide both sides by 5 )

x = 11

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Find the midpoint of the segment with the following endpoints. (6, 4) and (9, 1)​
joja [24]

Answer:

(\frac{15}{2},\frac{5}{2})

Hope this helps!

3 0
3 years ago
A distribution has a mean of 90 and a standard deviation of 15. Samples of size 25 are drawn randomly from the population. Find
raketka [301]

Answer:

The probability is 0.04746

Step-by-step explanation:

Firstly, we calculate the z-score here

Mathematically;

z-score = x-mean/SD/√n

Where from the question;

x = 85, mean = 90 , SD = 15 and n = 25

Plugging these values into the equation, we have;

Z = (85-90)/15/√25 = -5/15/5 = -1.67

So the probability we want to calculate is ;

P(z > -1.67)

We use the standard normal distribution table for this;

P(z > -1.67) = 0.04746

4 0
3 years ago
Suppose f is a continuous function on [-2, 2) such that
Leviafan [203]

Answer:

2. a and b only.

Step-by-step explanation:

We can check all of the given conditions to see which is true and which false.

a. f(c)=0 for some c in (-2,2).

According to the intermediate value theorem this must be true, since the extreme values of the function are f(-2)=1 and f(2)=-1, so according to the theorem, there must be one x-value for which f(x)=0 (middle value between the extreme values) if the function is continuous.

b. the graph of f(-x)+x crosses the x-axis on (-2,2)

Let's test this condition, we will substitute x for the given values on the interval so we get:

f(-(-2))+(-2)

f(2)-2

-1-1=-3  lower limit

f(-2)+2

1+2=3 higher limit

according to these results, the graph must cross the x-axis at some point so the graph can move from f(x)=-3 to f(x)=3, so this must be true.

c. f(c)<1 for all c in (-2,2)

even though this might be true for some x-values of of the interval, there are some other points where this might not be the case. You can find one of those situations when finding f(-2)=1, which is a positive value of f(c), so this must be false.

The final answer is then 2. a and b only.

4 0
4 years ago
What is the y-intercept of the line perpendicular to the line y = 3/4x + 3 that includes the point (-3, -3)
kipiarov [429]
A perpendicular line has an opposite reciprocal slope. This means that the new line will have a slope of -4/3x. Plug in x and y into the equation y=Mx +b where m is the slope (-4/3):
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b-3=(-3/4)(-3)
b=(-3/4)(-3) +3
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The final equation is y= -4/3x + 21/4
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3 years ago
Need help with these. please show work​
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Answer:

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