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Ad libitum [116K]
3 years ago
5

The Baines' house has a deck next to the living room. What is the total combined area of the living room and deck? 1. The deck a

nd living room combine to form a rectangle. What is the rectangle's width?
Mathematics
1 answer:
Vaselesa [24]3 years ago
6 0

Answer:

Well we need a diagram, see your book or the web from wherever you are asking this question.

Step-by-step explanation:

you gave to first find out the area of the room and the deck separately and then you will have to add them up.

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22/5 times 2 times 1/3
LUCKY_DIMON [66]

Answer:

44/15 or maybe 2 14/15

Step-by-step explanation:

4 0
3 years ago
Do not answer until you see an image, do not attempt to answer, or else I won't be able to edit it, also, only give the full ans
aleksley [76]
Range: 6.25
Interquartile range: 3:25
Would you like me to explain?
7 0
2 years ago
(1+cos2x)/(1-cos2x) = cot^2x
sesenic [268]

We will turn the left side into the right side.

\dfrac{1 + \cos 2x}{1 - \cos2x} = \cot^2 x

Use the identity:

\cos 2x = \cos^2 x - \sin^2 x

\dfrac{1 + \cos^2 x - \sin^2 x}{1 - ( \cos^2 x - \sin^2 x)} = \cot^2 x

\dfrac{1 - \sin^2 x + \cos^2 x }{1 - \cos^2 x + \sin^2 x} = \cot^2 x

Now use the identity

\sin^2 x + \cos^2 x = 1 solved for sin^2 x and for cos^2 x.

\dfrac{\cos^2 x + \cos^2 x }{\sin^2 x + \sin^2 x} = \cot^2 x

\dfrac{2\cos^2 x}{2\sin^2 x} = \cot^2 x

\dfrac{\cos^2 x}{\sin^2 x} = \cot^2 x

\cot^2 x = \cot^2 x


8 0
3 years ago
cos (x/2) = -sqrt2/2 in (0,360) looking for two values ?? Can someone please help me I can’t seem to figure out how to solve thi
ValentinkaMS [17]

Answer:

135° and 225°

Step-by-step explanation:

basically you want to find the value of x between 0 and 360 in this equation

cos x/2 = -(√2)/2

assume x/2 as n, so

cos n = -(√2)/2

n = 45°

then remember the quadrant system

0-90 1st quadrant, all is POSITIVE

90-180 2nd quadrant, only SIN has positive value

180 - 270 3rd quadrant, only TAN has positive value

270 -360 4th quadrant, only COS positive here.

so if you try to find negative value look into 2nd and 3rd quadrant that related 45° to x-axis (0°or 180°)

so the value of x is

180 - 45 = 135° (2nd quadrant) and

180 + 45° = 225° (3rd quadrant)

8 0
2 years ago
YO PLZ HELP!! MARKING BRAINIEST!!
Yuliya22 [10]

Answer:

x = 26, 16

Step-by-step explanation:

( x-21) ^2 = 25

Take the square root of each side

sqrt(( x-21) ^2) = ±sqrt(25)

x-21 = ±5

Add 21 to each side

x-21+21 = 21±5

x = 21±5

x = 21+5  and x = 21-5

x = 26, 16

8 0
3 years ago
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