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2 years ago

Solving Systems Using Inverses

Mathematics

1 answer:

Zanzabum2 years ago

7 0

Answer:

12x the second -12x -16

Step-by-step explanation:

Solving systems of equations with 3 variables is very similar

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If you roll a standard six sided dice, what is the probability you will roll a four?

astra-53 [7]

Answer:

1/6

Step-by-step explanation:

There are 6 sides on a dice. Every time you roll you you will have one of those sides. So it is a 1 in 6 chance of you getting 4, meaning that the answer to this problem is 1/6

7 0

3 years ago

What is the answer to this equation: 7.4 - 9 - 2r =18

lorasvet [3.4K]

We can get the answer to this equation by solving for the variable (r).

7.4 - 9 - 2r = 18

We want to get r on one side, so we want to push everything else to the other side.

-2r = 18 - 7.4 + 9

-2r = 19.6

2r = -19.6

r = -9.8

5 0

3 years ago

Read 2 more answers

Where do I find my work I did with a tutor?

OlgaM077 [116]

It should come up as a notification. Check your messages or press “tutor” maybe even try reloading the page.

8 0

2 years ago

Find the equation of the circle with a diameter whose end points are (-1,-2) and (-3,2)

Sergeeva-Olga [200]

Answer:

The equation of the circle with a diameter whose end points are (-1,-2) and (-3,2) is

$x^{2} +y^{2}+4x-1=0$

Step-by-step explanation:

Explanation:-

Step 1:-

The equation of the circle having center and radius is

$(x-h)^2+(y-k)^2=r^2$

here center is (h,k) and radius is r

Given diameter whose end points are (-1,-2) and (-3,2)

The diameter of the circle is passing through the center of the circle

so center of the circle = midpoint of two end points

$(\frac{-1 +(-3) }{2} ,\frac{-2+2 }{2} )$

$(-2,0)$

therefore center (h,k) = (-2,0)

Step 2:-

we have to find the radius of the circle

the radius of the circle = the distance from center to the one end point

i.e., C P = r

Given one end point is P(-3,2) and center C(-2,0)

The distance formula of two points are

$\sqrt{(x_{2}-x_{1} ) ^{2}+ (y_{2}-y_{1} ) ^{2}}$

$r=\sqrt{{(-3)-(-1) ) ^{2}+ (2-(-2)) ^{2}}$

$r=\sqrt{5}$

Step 3:-

center (h,k) = (-2,0) and

radius $r=\sqrt{5}$

The standard form of circle equation

$(x-h)^2+(y-k)^2=r^2$

$(x-(-2))^2+(y-0)^2=\sqrt{5} ^2$

on simplification is

$x^{2} +y^{2}+4 x-1=0$

5 0

2 years ago

Factor X-7X -5x + 35 by grouping. What is the resulting expression?

Yuliya22 [10]

The answer is c). (x-5)(x-7)

7 0

3 years ago