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sergiy2304 [10]

3 years ago

8

I need help on this question, not to good with graph. Anybody help pleaseee!!

1 answer:

LenKa [72]3 years ago

3 0

y = -3x - 2

Since a < 0 we have a decreasing line, so it can be only the first or the last

And if we solve the equation for y = 0 we have

0 = -3x - 2

3x = -2

x = -2/3

So, the last one is the right

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Which expression is equivalent

Tatiana [17]

Given expression is

$\sqrt[4]{\frac{16x^{11}y^8}{81x^7y^6}}$

Radical is fourth root

first we simplify the terms inside the radical

$\frac{x^{11}}{x^7}=x^4$

$\frac{y^(8)}{y^6}=y^2$

So the expression becomes

$\sqrt[4]{\frac{16x^4y^2}{81}}$

Now we take fourth root

$\sqrt[4]{16} = 2$

$\sqrt[4]{81} = 3$

$\sqrt[4]{x^4} = x$

We cannot simplify fourth root (y^2)

After simplification , expression becomes

$\frac{2x\sqrt[4]{y^2}}{3}$

Answer is option B

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3 years ago

Why is ac smaller than ad if they both look very close

kakasveta [241]

Let's begin by listing out the information given to us:

We start out by observing that Triangles MKR & ACD are similar or proportional

$\begin{gathered} MK=21;AC=\text{?} \\ MR=24;AD=28\frac{4}{5} \\ KR=CD=\text{?} \end{gathered}$

We will solve for the missing side by using the similar triangle theorem. This is shown below:~

$\begin{gathered} \Delta MKR\approx\Delta ACD \\ \frac{MK}{AC}=\frac{MR}{AD} \\ \frac{21}{AC}=\frac{24}{28\frac{4}{5}} \\ \text{Cross multiply, we have:} \\ 24\cdot AC=28\frac{4}{5}\cdot21 \\ AC=\frac{28\frac{4}{5}\cdot21}{24}=25\frac{1}{5} \\ AC=25\frac{1}{5} \end{gathered}$

8 0

1 year ago

Use quadratic equation to find the roots of the following equations

sertanlavr [38]

See the attachment below.

Hope it helps!

3 0

3 years ago

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the sum of the reversed number and the original number is 154. Find the original number, if the ones digit in it is 2 less than

VladimirAG [237]

Answer:

The number is 86

Step-by-step explanation:

Let the number be $xy$ , then the reverse is $yx$

The sum of the reversed number and the original number is 154,

$\implies (10x+y)+(10y+x)=154$

We simplify this to get:

$\implies 11x+11y=154$ ....eqn(1)

If the ones digit in it is 2 less than the tens digit, then

$y=x-2$ ....eqn(2)

Putt equation (2) in (1)

$\implies 11x+11(x-2)=154$

$\implies 11x+11x-22=154$

$\implies 11x+11x=154+22$

$\implies 22x=176$

$\implies x=8$

Put x=8 in the second equation:

$y=8-2=6$

The original number is 86

7 0

3 years ago

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Please help I am confused i'll answer one of your questions!! I got it wrong the first time

vaieri [72.5K]

Answer:

Step-by-step explanation:

22.2

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3 years ago

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