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2 years ago

15

in the figure above, bc and ad are parallel, ab and ec are parallel, cd=ce, and the measure of angle abc is 115 degrees. what is

the measure of angle bcd

1 answer:

bonufazy [111]2 years ago

7 0

Answer:

"in the figure above" ?

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7p²-30p + 8 how do you factor this trinomial

tamaranim1 [39]

Step-by-step explanation:

7p²-30p+8

=(p-4)(7p-2)

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3 years ago

Use the definition of a derivative to find f’(x).

tatyana61 [14]

Answer:

f'(x) = $-\frac{9}{x^2}$

Step-by-step explanation:

i) f(x) = 9 / x

ii) f'(x) = $$\lim_{h\to 0} \frac{f(x+h) - f(x)}{h} $ \hspace{0.2cm}$

$= $\lim_{h\to 0} \frac{\frac{9}{x+h} - \frac{9}{x} }{h} = \hspace{0.1cm} $\lim_{h\to 0} \frac{9x - 9(x+h)}{hx(x+h)} $ \hspace{0.1cm} = \hspace{0.1cm}$\lim_{h\to 0} \frac{-9h}{hx(x+h)} = $\lim_{h\to 0} \frac{-h}{x(x+h)} = \frac{-9}{x^2}$$

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3 years ago

If the two terms of a gemotric sequence are a1=216, and a2=72, which is the third term? a3?

Ierofanga [76]

$GEOMETRIC \: \: PROGRESSIONS \\ \\ \\\\Let \: the \: G.P. \: be \: \: A \: , \: Ar \: , \: A {r}^{2} \: ... \\ \\ Where \:first \: term \: is \: \: A \: \: \\ and \: common \: ratio \: is \: \: R \\ \\ Let \: An \: denotes \: the \: \: nth \: term \: of \: \\ the \: given \: Geometric \: Progression \: \\ \\ It \: is \: given \: - \\ \\ A1 \: = \: 72 \\ \\ A2 \: = \: 216 \\ \\ Common \: ratio \: = \: \frac{A2}{A1} = \frac{216}{72} \\ \\ R = 3 \\ \\ A \: = \: 72 \\ \\ A3 \: = \: A {r}^{2} = 72 \times 3 \times 3 \\ \\ \\ Hence \: , \: A3 \: = \: 648 \: \: \: \: \: \: \: Ans.$

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3 years ago

What is the reciprocal of 6 3/7?

77julia77 [94]

I believe your answer is going to be -6 7/3. Reciprocals are the opposites of a number, so I switched the sign on the 6 and made it -. When dealing with fractions, the reciprocal is essentially just flipping the numerator and denominator, which is how I got 7/3.

I hope I helped. Best of luck!

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3 years ago

Read 2 more answers

Help!!!! Plssss!!! ASAP

zimovet [89]

Answer:

The y-intercept is (0,-26)

Step-by-step explanation:

Given two points P(a,b) and Q(c,d), the line that passes for both points can be found with the expression

$\displaystyle y-b=\frac{d-b}{c-a}(x-a)$

We'll take the first two points P(34,-52) and Q(51,-65) to find

$y=-\frac{13}{17}(x-34)-52\\ \\y=-\frac{13}{17}x-26$

Let's verify if the third point is on the line:

$y=-\frac{13}{17}68-26=-52-26=-78$

It belongs to the line. To find the y-intercept of the line, we set x to 0

$y=-\frac{13}{17}(0)-26=-26$

The y-intercept is (0,-26)

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3 years ago