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andrey2020 [161]
3 years ago
8

Value of x!!!! THANKS LAST ONE!!!

Mathematics
1 answer:
notka56 [123]3 years ago
7 0

Answer:

45

Step-by-step explanation:

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1. P, Q and R are three buildings. A car began its journey at P, drove to Q, then to R and returned to P. The bearing of Q from
juin [17]

Statement Problem: P, Q and R are three buildings. A car began its journey at P, drove to Q, then to R and returned to P. The bearing of Q from P is 058° and R is due east of Q. PQ = 114 km and QR = 70 km. ( Draw a clearly labelled diagram to represent the above information.

Solution:

8 0
2 years ago
Are You guys up for math?? Its 6th grade math though!! so are you ready?? l want help please.
katen-ka-za [31]

The ratio would be 4:1.

Try to reduce the ratio further with the greatest common factor (GCF).

The GCF of 64 and 16 is 16

Divide both terms by the GCF, 16:

64 ÷ 16 = 4

16 ÷ 16 = 1

The ratio 64 : 16 can be reduced to lowest terms by dividing both terms by the GCF = 16 :

64 : 16 = 4 : 1

Therefore:

64 : 16 = 4 : 1

3 0
3 years ago
18
GalinKa [24]

Answer:

18

ZAOC and ZCOB are supplementary angles.

Find the

6 0
3 years ago
Please do not claim this unless you answer the question.
anygoal [31]
Negative , you always put the biggest numbers value at the end
7 0
1 year ago
Read 2 more answers
A health food company packs almond butter in jars. Some jars hold 250 g. Other jars hold 500 g. On Tuesday, the company packed 1
MArishka [77]
Let the number of 250g=0.25  kg jars be x and that of 500g=0.5 kg jams be y;
therefore:
total number of jars ws
x+y=511
x=511-y..........i

total mount kgs was:
0.25x+0.5y=186.5....ii
substituting i in ii
0.25(511-y)+0.5y=186.5
127.75-0.25y+0.5y=186.5
solving for y we get:
0.25y=186.5-127.75
0.25y=58.75
y=58.75/0.25
y=235 jars
and 
x=511-x
=511-235
=276
hence we conclude that there was 235 jars with 0.5 kg almond and 276 jars with 0.25 kg almonds
5 0
3 years ago
Read 2 more answers
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