1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Vesnalui [34]
2 years ago
10

What is (- 2g-6)-(g-10)

Mathematics
2 answers:
docker41 [41]2 years ago
6 0

Answer:

Step-by-step explanation

(-2g-6)-\left(g-10\right)

(−2g−6)−(g−10)

EleoNora [17]2 years ago
3 0

Answer:

-3g + 4

Step-by-step explanation:

You might be interested in
(3x + 1/2 ) + ( 7x - 4 1/2 ) simply the expression
ololo11 [35]

(3x + 1/2 ) + ( 7x - 4 1/2 )

3x+7x + 1/2 - 4 1/2

10x -4

5 0
3 years ago
Help I’ll give brainliest
pychu [463]

Answer:

The 5th is correct.

Step-by-step explanation:

The ratio of orange juice (1) to raspberry juice (1) is 1 to 1.

4 0
3 years ago
Read 2 more answers
20. The surface areas of two similar solids are 216 m² and 1014 m². The volume of the larger one is 2197 m³. What is the volume
Andrei [34K]

Answer:

  216 m³

Step-by-step explanation:

The ratio of linear dimensions is the square root of the ratio of area dimensions.

  s = √(216/1014) = √(36/169) = 6/13

Then the ratio of volume dimensions is the cube of that. The smaller volume is ...

  v = (6/13)³·2197 m³ = 216/2197·2197 m³ = 216 m³

The volume of the smaller solid is 216 m³.

8 0
3 years ago
Given two dice, what is the probability of rolling a four on the second die, given that you already rolled a four on the first d
Sholpan [36]

Answer:   1/6

Reason:

There's 1 side labeled "4" out of 6 sides total. So that's where the 1/6 comes from.

The "given that you already rolled a four on the first die" is unneeded info in my opinion, because each die is separate or independent from one another.

8 0
2 years ago
If 15 actuators have failed today, what is the probability that a) at least 10 are repairable? b) from 3 to 8 are repairable? c)
Ann [662]

The probabilities of at least 10 are repairable is 1/3. and probabilities of from 3 to 8 are repairable is 1/5*8/15 and probabilities of exactly 5 are repairable is 1/3.

According to the statement

we have given that If 15 actuators have failed and we have to find the probabilities on some conditions.

we know that the formula of probabilities is

probability = possible outcomes / total outcomes

So,

  • at least 10 are repairable = 1 - (10 are not repairable)

at least 10 are repairable = 1 - 10/15

at least 10 are repairable = (15 - 10)/15

at least 10 are repairable = (5)/15

at least 10 are repairable = 1/3

  • from 3 to 8 are repairable = 3/15 *8/15

from 3 to 8 are repairable = 1/5 *8/15

  • exactly 5 are repairable = 5/15

exactly 5 are repairable = 1/3

These are the probabilities of the given conditions.

So, The probabilities of at least 10 are repairable is 1/3. and probabilities of from 3 to 8 are repairable is 1/5*8/15 and probabilities of exactly 5 are repairable is 1/3.

Learn more about PROBABILITIES here brainly.com/question/25870256

#SPJ4

6 0
2 years ago
Other questions:
  • Fred has saved 4300 cent over 2 days from selling lemonade. how many dollars dose fred have ?
    15·2 answers
  • If y =-5 when x =12.5 find x when y =15
    15·1 answer
  • What is the area of the parallelogram
    15·2 answers
  • Indentify the y-intercept of the graph below
    5·1 answer
  • What is the missing numerator?
    11·1 answer
  • Last year Chesa made 32 one-cup servings of soup for a school party. This year, she will make two times the amount of soup that
    6·1 answer
  • PLEASE HELP!! NO LINKS!!
    11·1 answer
  • The International Air Transport Association surveys business travelers to develop quality ratings for transatlantic gateway airp
    11·1 answer
  • Rewrite 1/3 book - 5/6 hour as a unit rate.
    5·1 answer
  • Use the following variables for #'s<br><br>(3-5):<br><br>f= -6 g= 7 h=9<br><br><br>4) 5-f
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!