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Goshia [24]
3 years ago
6

∠A and \angle B∠B are complementary angles. If m\angle A=(2x+10)^{\circ}∠A=(2x+10)

Mathematics
1 answer:
vlada-n [284]3 years ago
3 0

Answer:

Step-by-step explanation:

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The common ratio in a geometric series is 0.50.50, point, 5 and the first term is 256256256.
V125BC [204]

Answer:

504

Step-by-step explanation:

I think the correct question is like:The common ratio in a geometric series is 0.50 ( point 5) and the first term is 256.  

Find the sum of the first 6 terms in the series.

If it's right, then

Sₙ = (a₁ * (1 - rⁿ)) / (1 - r)

S₆ = (256 * ( 1 - 0.5⁶)) / (1 - 0.5) = (256 * 0.984375) / 0.5 = 504

6 0
3 years ago
Indicate the equation of the line, in standard form, that is the perpendicular bisector of the segment with endpoints (4, 1) and
jenyasd209 [6]

Equation of a line is x+3y =-3.

<h3>What is a perpendicular bisector of the line segment?</h3>

A perpendicular bisector is a line that cuts a line segment connecting two points exactly in half at a 90 degree angle. To find the perpendicular bisector of two points, all you need to do is find their midpoint and negative reciprocal, and plug these answers into the equation for a line in slope-intercept form.

Given that,

Endpoints of the line segment are (x_{1},y_{1}) = (4, 1) and (x_{2},y_{2}) = (2, -5).

First find the midpoints of the given line segment.

M = \left(\frac{x_{1}+x_{2}  }{2},\frac{y_{1}+y_{2}  }{2}\Right)

    =  \left(\frac{4+2  }{2},\frac{1-5  }{2}\Right)

M   =  (3,-2)

Now, Find the slope of the line :

It is perpendicular to the line with (4,1) and (2,-5)

Slope between (x_{1},y_{1}) and (x_{2},y_{2}) = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

so,

the slope between (4,1) and (2,-5)  =  \frac{-5-1  }{2-4 }

                                                         = 3

perpendicular lines have slopes the multiply to get -1

3 times m=-1

m= \frac{-1}{3}

The equation of a line that has a slope of m and passes through the midpoints M(3,-2)  is

y-y_{1} =m(x-x_{1} )

y-(-2) =\frac{-1}{3} (x-3 )

(y+2) =\frac{-1}{3} (x-3 )

if we want slope intercept form

(y+2) =\frac{-1}{3} x+1

y= \frac{-1}{3} x-1

If we want standard form

\frac{1}{3} x+y = -1

x+3y =-3

Hence, Equation of a line is x+3y =-3.

To learn more about perpendicular bisector of the line segment from the given link:

brainly.com/question/4428422

#SPJ4

   

7 0
1 year ago
Need help with math problem if do get 5 star
11Alexandr11 [23.1K]
<h3><u>Answer</u><u>:</u></h3>

  • The point ( 22 , 23 ) lies in Ist quadrant

<h3><u>Explanation</u><u>:</u></h3>

The intersection of x and y axis divides the coordinate plane into 4 sections. These four sections are called quarrants. These quadrants are named as Roman numerals I, II, III and IV quadrant. The start with the top right corner and move in anti clockwise direction .

  • In a x y plane , both the values of x and y are positive in Ist quadrant
3 0
2 years ago
Definition: In x3, x is called the
Arturiano [62]

Answer:

it is exponent less than 1

3 0
3 years ago
Find the error in the student's work. Which of the following steps is where the first error occurred?
Stels [109]

Answer:

Step 1 should have a -2 substituted for both values.

5 0
3 years ago
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