∠A and \angle B∠B are complementary angles. If m\angle A=(2x+10)^{\circ}∠A=(2x+10)

Katt and sanjeev are collecting money for charity. For every £2 that kat collects, sanjeev collects £3. They collect £255 in tot

il63 [147K]

Answer: Kate = £102

Sanjeev = £153

Step-by-step explanation:

From the question, we are informed that for every £2 that kat collects, sanjeev collects £3. This csn be represented in a fraction as:

Kat = 2/5

Sanjeev = 3/5

The amount that each collects will be:

Kat = 2/5 × £255

= 2 × £51

= £102

Sanjeev = 3/5 × £255

= 3 × £51

= £153

6 0

3 years ago

Draw the multiplication table on the P=(3,5,7,9) in module 12

Lisa [10]

Answer:

Find the attached file for the solution

Step-by-step explanation: To draw the multiplication table on the P=(3,5,7,9) in module 12, create the table where all the given parameters will be at the top of horizontal axis and vertical axis,

When multiply by each other, any value that is below 12 will be written down while the value greater than 12 will be divided by 12 and the remainder will be written down.

Find the attached file for the solution and table.

8 0

3 years ago

Solve the equation for x.

valentina_108 [34]

Answer:

Solve for

x

by simplifying both sides of the equation, then isolating the variable.

Exact Form:

x

=

5 /4

Decimal Form:

x

=

1.25

Mixed Number Form:

x

=

1 1/4

Step-by-step explanation:

THE ANSWER IS C

4 0

3 years ago

Felipe is ordering new carpet for his bedroom floor. (The floor is represented in the picture below as rectangle JKLM). He knows

svetlana [45]

Answer: 312.3 square feet

Step-by-step explanation:

7 0

3 years ago

Scores on a university exam are Normally distributed with a mean of 78 and a standard deviation of 8. The professor teaching the

mafiozo [28]

Answer:

Porcentage of students score below 62 is close to 0,08%

Step-by-step explanation:

The rule

68-95-99.7

establishes:

The intervals:

[ μ₀ - 0,5σ , μ₀ + 0,5σ] contains 68.3 % of all the values of the population

[ μ₀ - σ , μ₀ + σ] contains 95.4 % of all the values of the population

[ μ₀ - 1,5σ , μ₀ + 1,5σ] contains 99.7 % of all the values of the population

In our case such intervals become

[ μ₀ - 0,5σ , μ₀ + 0,5σ] ⇒ [ 78 - (0,5)*8 , 78 + (0,5)*8 ] ⇒[ 74 , 82]

[ μ₀ - σ , μ₀ + σ] ⇒ [ 78 - 8 , 78 +8 ] ⇒ [ 70 , 86 ]

[ μ₀ - 1,5σ , μ₀ + 1,5 σ] ⇒ [ 78 - 12 , 78 + 12 ] ⇒ [ 66 , 90 ]

Therefore the last interval

[ μ₀ - 1,5σ , μ₀ + 1,5 σ] ⇒ [ 66 , 90 ]

has as lower limit 66 and contains 99.7 % of population, according to that the porcentage of students score below 62 is very small, minor than 0,15 %

100 - 99,7 = 0,3 %

Only 0,3 % of population is out of μ₀ ± 1,5 σ, and by symmetry 0,3 /2 = 0,15 % is below the lower limit, 62 is even far from 66 so we can estimate, that the porcentage of students score below 62 is under 0,08 %

6 0

3 years ago