Data:
solute: ethylene glicol => not ionization
molar mass of ethylene glicol (from internet) = 62.07 g/mol
solute = 400 g
solvent = water = 4.00 kg
m =?
ΔTf = ?
Kf = 1.86 °C/mol
Formulas:
m: number of moles of solute / kg of solvent
ΔTf = Kf*m
number of moles of solute = mass in grams / molar mass
Solution
number of moles of solute = 400 g / 62.07 g/mol = 6.44 moles
m = 6.44 mol / 4 kg = 1.61 m <-------- molality (answer)
ΔTf = 1.86 °C / m * 1.61 m = 2.99 °C <---- lowering if freezing point (answer)
Answer:
X is 3-chloro-2,4-dimethylpentane
Explanation:
The radical chlorination of 2,4-dimethylpentane may give three products.
Based on the information that
i) both the products gives single alkene on elimination and
ii) both the products also undergoes SN2 reaction but Y reacts faster than X
We may conclude that as SN2 reaction is faster in primary alkyl halides as compared to secondary or tertiary so Y must be primary or secondary and it cannot be tertiary alkyl halide.
The possible products are shown in the figure.
The structure of X is shown in the figure.
What words are you looking for so i dont put them down