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allochka39001 [22]
3 years ago
7

Atoms of which element contain 25 protons? magnesium (Mg) aluminum (Al) tin (Sn) manganese (Mn)

Chemistry
1 answer:
Rashid [163]3 years ago
6 0
Manganese since the atomic number is 25
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Explanation:

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A horizontal cylinder equipped with a frictionless piston contains 785 cm3 of steam at 400 K and 125 kPa pressure. A total of 83
guapka [62]

Answer:

a. 478.69 K

b. 939.43 cm^{3}

c. 19.30 J

d. 64.5J

Explanation:

From the question, we can identify the following;

V_{o} = 785cm^{3} = 0.000785 m^{3}

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Thus, n = PV/RT = (125000 × 0.000785)/(8.314 × 400) = 0.03 mol

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To calculate this, we use the constant pressure process;

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Thus;

83.8 = 0.03 × [34980 + 35.5T_{1} - (34980 + 35.5T_{o})]

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83.8 = 1.065 (T_{1}  - 400)

78.69 = (T_{1}  - 400)

T_{1} = 400 + 78.69

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b. Final cylinder volume

To calculate this, we make use of the Charles' law(Temperature and pressure are directly proportional)

V_{1}/T_{1} = V_{o}/T_{o}

V_{1}  =  V_{o}T_{1}/T_{o}

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V_{1}   = 939.43 cm^{3}

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Mathematically, the work done by the system is calculated as follows;

w = P(V_{1}- V_{o}) = 125 KPa ( 939.43 - 785) = 19.30 J

d. Change in internal energy of the steam in J

ΔU = q - w = 83.8 - 19.3 = 64.5J

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