Answer:
P(total) = 1329 torr
Explanation:
Given data:
Pressure of nitrogen = 984 torr
Pressure of carbon dioxide = 345 torr
Total pressure of system = ?
Solution:
The given problem will be solve through the Dalton law of partial pressure of gases.
According to the this law,
The total pressure exerted by the mixture of gases is equal to the sum of partial pressure of individual gas.
Mathematical expression,
P(total) = P₁ + P₂ +.......+ Pₙ
Here we will put the values in formula,
P₁ = partial pressure of nitrogen
P₂ = partial pressure of carbon dioxide
P(total) = 984 torr + 345 torr
P(total) = 1329 torr
Answer:
A) pH = 8.11
B) pH = 7.96
Explanation:
The pH of buffer is calculated using Henderson Hassalbalch's equatio, which is
![pH=pKa+log\frac{[salt]}{[acid]}](https://tex.z-dn.net/?f=pH%3DpKa%2Blog%5Cfrac%7B%5Bsalt%5D%7D%7B%5Bacid%5D%7D)
pKa = -logKa = -log(3.0 ✕ 10⁻⁸)
pKa = 7.5
[salt] = 0.667
[Acid] = 0.214

A) If the solution is halved it means the concentration of both salt and acid will be the same.
The volume will change
Number of moles of acid = molarity X volume = 0.214 X 25 = 5.35 mmol
Number of moles of salt = molarity X volume = 0.667 X 25 = 16.68 mmol
moles of NaOH added = molarity X volume = 0.100 X 10 = 1 mmol
These moles of NaOH will react with acid to give same amount of salt and thus the moles of acid will decrease
New moles of acid = 5.35 - 1 = 4.35
New moles of salt = 16.68 + 1 = 17.68
the new pH will be

B)
moles of HCl added = molarity X volume = 0.100 X 10 = 1 mmol
These moles of HCl will react with salt to give same amount of acid and thus the moles of salt will decrease
New moles of acid = 5.35 + 1 = 6.35
New moles of salt = 16.68 - 1 = 15.68
the new pH will be

The answer would be 4,000
Because 474 is gonna go down but if it was 500 it will go up
Answer:
The answer to your question is the first option
Explanation:
Just remember that to balance using this method,
first look for the elements that change their oxidation number, and
later count the number of electrons that changed,
later identify which element oxidazes and which reduces and
finally cross the number of electrons that change in each semireaction and write these numbers in the main reaction.
2Cr⁺³ (aq) + 6Cl⁻ (aq) ⇒ 2Cr(s) + 3Cl₂ (g)
2 Cr 2
6 Cl 6