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Rasek [7]
2 years ago
14

2. A pharmaceutical company scientist is testing whether the mean level of a toxin in a newly created children’s medicine is les

s than 5mg, a level which could damage the children taking it.
a. If the test were conducted on a sample of 5,000 bottles, explain how the results could give significant results, but still make the company hesitant about making the medicine.

b. 5% is a very common significance level for significance tests, but it Is arbitrary. In this case explain what you might change the significance level to and why you would consider changing it.
Mathematics
1 answer:
Alexus [3.1K]2 years ago
8 0

Answer:

then i juuy

Step-by-step explanation:

hen ju b n[k

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Match the following terms by evaluating the expression for x=-6
Scorpion4ik [409]
The sum of 2 opposites =0
X+6 would now equal 0
So your answer is 0
5 0
4 years ago
<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B11%7D%7B17%7D%20%20%5Cdiv%20%20%5Cfrac%7B7%7D%7B10%7D%20" id="TexFormula1" title=
Lilit [14]

Your answer is 110/119

11/17 Divided By 7/10

11 * 10

17 * 7

110/119

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8 0
3 years ago
Read 2 more answers
Find the nth term of the arithmetic sequences<br> a1=5,d=6,n=11
ki77a [65]

here's the solution,

  • n = 11
  • a = 5 ( a = first term )
  • d = 6 ( d = common difference )

we know,

=》

nth  \: \: term \:  = a   \: + (n - 1) \times d

=》

11th \:  \: term   = 5 + (11 - 1) \times 6

=》

11th \:  \: term = 5 + (10 \times 6)

=》

11th \:  \: term  = 5 + 60

=》

11th \:  \: term = 65

nth term ( 11th term ) = 65

3 0
3 years ago
The equation of a circle is ​x2+4x+y2−10y+13=0​ .
kiruha [24]
X^2+4x+4+y^2-10y+25=-13+25+4

(x+2)^2 + (y-5)^2= 16
Third option
8 0
4 years ago
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our buses carrying 140 high school students arrive to Montreal. The buses carry, respectively, 31, 43, 27, and 39 students. One
Vinvika [58]

Answer:

V(X)= 39.10

V(Y)= 40

Step-by-step explanation:

Given that

Total number of student = 140

Bus A - 31

Bus B- 43

Bus C- 27

Bus D- 39

The probability that a student was on the bus is proportional to the number of student. Eg 31/140 in bus A, 43/140 on bus B, ...

E(X) = (31*31/140) + (43*43/140)  + (27*27/140) + (39*39/140)

=  35.5

Var(X) =(31-35.5)^2 \times \dfrac{31}{140}+(43-35.5)^2 \times \dfrac{43}{140}+(39-35.5)^2 \times \dfrac{39}{140}+(27-35.5)^2 \times \dfrac{27}{140}

V(X)= 39.10

The bus driver have  1/4 probability on being on any of the buses.

E(Y) = 140/4 = 35

Var(Y)=\dfrac{(35-31)^2+(35-43)^2+(35-27)^2+(35-39)^2}{4}

V(Y)= 40

7 0
3 years ago
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