840 centimeters ...there 100 centimeters in one meter
The answer is Option B. It would be cheaper for Miguel to drive 200 miles with Option B than Option A.
Answer: a) (0.755, 0.925)
Step-by-step explanation:
Let p be the population proportion of 8th graders are involved with some type of after school activity.
As per given , we have
n= 100
sample proportion: 
Significance level : 
Critical z-value :
(using z-value table)
Then, the 98% confidence interval that estimates the proportion of them that are involved in an after school activity will be :-

i.e. 
i.e. 
i.e. 
Hence, the 98% confidence interval that estimates the proportion of them that are involved in an after school activity : a) (0.755, 0.925)
Since all you’re saying is evaluate ∫12–2
I’m assuming the answer would be 1/(1+x)(1-x)
Answer:
6.8% decrease
Step-by-step explanation:
a drop of 8% means that only 92% of 125 boys remained on honor roll from last year; .92 x 125 = 115
a drop of 5% means that only 95% of 80 girls remained on honor roll from last year; .95 x 80 = 76
total number of students on honor roll last year = 125 + 80 = 205
total number of students on honor roll this year = 115 + 76 = 191
percent of change = (191 - 205) ÷ 205 = -14/205 = -.068
-.068, which represents a 6.8% decrease