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Roman55 [17]
2 years ago
7

NEED RN, WORTH 30! ~ please and thank you! <3

Mathematics
1 answer:
rosijanka [135]2 years ago
8 0
1/4x-4 so the second one
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What is the equation parallel to 4y-3x=8
Andreyy89

Answer:

Whatever option has a slope of 3/4 and isn't y = 3/4x + 2

Step-by-step explanation:

This means that it has to have a slope of 3/4 (written as 3/4x + b). This is because parallel lines have the same slope; rearranging the first equation gets us y = 3/4x + 2. So, our slope for a parallel line has to be 3/4.

6 0
3 years ago
X×9=y, y-70=11 , y=?​
solmaris [256]

Answer:

y=81

Step-by-step explanation:

x=9 and y=81

y-70=11 (add 70 onto 11)

y=81

5 0
2 years ago
Read 2 more answers
In the figure shown, line AB is parallel to line CD.
disa [49]

Answer:

Part A: <em>x = </em>55°

Step-by-step explanation:

<em>Part A Work:</em>

x + 65 = 120

<em>Part B Work:</em>

<em> </em>The transversal passes through the 2 conforming lines which allows you to use rules such as opposing interior angles. <em> </em>

<em> </em>

<em>hope this helps!</em>

<em>- Kiniwih426</em>

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4 0
3 years ago
Find a polynomial P(x) with real coefficients having a degree 4, leading coefficient 4, and zeros 3-i and 4i.
Alisiya [41]

now, this polynomial has roots of 3-i and 4i, namely 3 - i and 0 + 4i.

let's bear in mind that a complex root never comes all by her lonesome, her sibling is always with her, the conjugate, so if 3 - i is there, 3 + i is also coming along, likewise if 0 + 4i is there, her sibling 0 - 4i is also there.

\bf \begin{cases} x=3-i\implies &x-3+i=0\\ x=3+i\implies &x-3-i=0\\ x=4i\implies &x-4i=0\\ x=-4i\implies &x+4i=0 \end{cases}\\\\[-0.35em] ~\dotfill\\\\ (x-3+i)(x-3-i)(x-4i)(x+4i)=\stackrel{y}{0} \\[2em] \underset{\textit{difference of squares}}{[(x-3)+i][(x-3)-i]}\underset{\textit{difference of squares}}{[x-4i][x+4i]}=0

\bf [(x-3)^2-i^2][x^2-(4i)^2]=y\implies [(x-3)^2-(-1)][x^2-(4^2i^2)]=0 \\[2em] [(x-3)^2-(-1)][x^2-(16(-1))]=0\implies [(x-3)^2+1][x^2+16]=0 \\[2em] [(x^2-6x+9)+1][x^2+16]=y\implies (x^2-6x+10)(x^2+16)=0 \\\\\\ x^4-6x^3+10x^2+16x^2-96x+160=0 \\\\\\ x^4-6x^3+26x^2-96x+160=0 \\\\\\ \stackrel{\textit{multiplying both sides by 4}}{4(x^4-6x^3+26x^2-96x+160)=4(0)} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill 4x^4-24x^3+104x^2-384x+640=y~\hfill

3 0
3 years ago
dude, I just got almost all of my points taken away from somebody that has 0 answers, 0 questions, and almost 2 million points..
Finger [1]

Answer:

:O

Step-by-step explanation:

7 0
2 years ago
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