Graph the line with the equation y = -x - 3.

Mathematics

1 answer:

larisa [96]2 years ago

8 0

Answer:

Step-by-step explanation:

$y=-x-3$

This means a graph with a slope of -1, and a y-intercept of -3

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What is the solution for this inequality? -10x ≤ 40 A. x ≤ -4 B. x ≤ 4 C. x ≥ -4 D. x ≥ 4

inessss [21]

Answer:

C. x ≥ -4

General Formulas and Concepts:

Pre-Algebra

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Step-by-step explanation:

Step 1: Define

Identify

-10x ≤ 40

Step 2: Solve for x

[Division Property of Equality] Divide -10 on both sides: x ≥ -4

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3 years ago

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At a amusement ,park 360 visitors rode the roller coaster in 3 hours.Write and solve a proportion to find the number of visitors

Pachacha [2.7K]

First you need to find out about how many people went on the roller coaster in one hour by doing 360 divided by 3 and you would get 120. So then you would try to find out how many people went on the coaster in 7 hours by doing 360 times 2 because 3 hours multiplied by 2 is 6 and you would do that to find out how many people went on the coaster in 6 hours, and you would get 720. Next, you have 1 more round of people, so you need to do 720 + 120 which is 840. So about 840 people rode the coaster in 7 hours. Hope this helped.

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3 years ago

Use the four-step definition of the derivative to find f'(x) if f(x) = −4x^3 −1.

guapka [62]

$\stackrel{de finition \textit{ of a derivative as a limit}}{\lim\limits_{h\to 0}~\cfrac{f(x+h)-f(x)}{h}} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{[-4(x+h)^3-1]~~ - ~~[-4x^3-1]}{h} \\\\\\ \cfrac{[-4(x^3+3x^2h+3xh^2+h^3)-1]~~ ~~+4x^3+1}{h} \\\\\\ \cfrac{[-4x^3-12x^2h-12xh^2-4h^3-1]~~ ~~+4x^3+1}{h} \\\\\\ \cfrac{-4x^3-12x^2h-12xh^2-4h^3-1+4x^3+1}{h}\implies \cfrac{-12x^2h-12xh^2-4h^3}{h}$

$\cfrac{h(-12x^2-12xh-4h^2)}{h}\implies -12x^2-12xh-4h^2 \\\\\\ \lim\limits_{h\to 0}~-12x^2-12xh-4h^2\implies \lim\limits_{h\to 0}~-12x^2-12x(0)-4(0)^2 \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \lim\limits_{h\to 0}~-12x^2~\hfill$