Answer:
so this one could be a little tricky to understand over the computer.Im going to try my best though.
Step-by-step explanation:
Its hard to explain how i got the answer.
im not going to try and do it.
7-5
8-2.5
really hope this helps. :)
Answer:
I would say 5.2 .
Step-by-step explanation:
if I’m wrong, I’m sorry. If I’m right, mark me brainlest!
The tensile strength of spider silk is about 1150 MPa, which is 1.15 x 10^9 N/m².
<span>So given that the diameter of the spider silk is 0.15 mm or 1.5 x 10^-4 m. The cross sectional area is approximately: </span>
<span>A = πr² = (3.14)(1.5 x 10^-4 / 2)² = 1.767 x 10^-8 m² </span>
<span>So this means that the amount of force we can apply before the the silk thread is broken is: </span>
<span>F = PA = (1.15 x 10^9)(1.767 x 10^-8) = 20.32 N </span>
<span>F = mg, so m = F/g = (20.32)/(9.81) = 2.07 kg!!! </span>
Their sum would be of odd number....
