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Scilla [17]
3 years ago
8

A computer can process the payroll for Hometel in 10 hours. An older back up computer needs 11 hours to

Mathematics
1 answer:
dem82 [27]3 years ago
4 0

Both computers will do the job in 5 hours and 14 minutes.

Since a computer can process the payroll for Hometel in 10 hours, while an older back up computer needs 11 hours to process payroll, to determine how long would the job take if the two computers are both used to do the job, the following calculation should be performed:

  • X / 10 + X / 11 = 1
  • 10X + 11X = 110
  • 21X = 110
  • X = 110/21
  • X = 5.238  
  • 100 = 60
  • 0.238 = X
  • 0.238 x 60/100 = X
  • 0.14 = X

Therefore, both computers will do the job in 5 hours and 14 minutes.

Learn more in brainly.com/question/14585276

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$1,500 pesos to USD

1500 ÷13.5 = 111.11

Around $111.11 USD Rounded to the nearest Hundreth.
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4 years ago
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Middle School teaches 6th, 7th, and 8th grade classes. The sixth grade has 318 students, the 7th has 286 students, and the 8th h
Ierofanga [76]

Answer:

$3185

Step-by-step explanation:

Multiply the number of grade 6 students by the money needed ($3.50) and you get 318x3.50=1113

Multiply the number of grade 7 students by the money needed ($3.50) and you get  286x3.50=1001

Multiply the number of grade 8 students by the money needed ($3.50) and you get 306x3.50=1071

Add all the total amounts together and you get $3185

8 0
3 years ago
Please solve or help:)
Nimfa-mama [501]

Step-by-step explanation:

please mark me as brainlest

3 0
3 years ago
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1A research firm finds that the average number of customers that are in Somerset Mall on a
SpyIntel [72]

Answer: C(t) = -475.5*cos(t*pi/6) + 475.5

Step-by-step explanation:

We know that we have a sinusoidal relation, with a minimum at 9:00 am and at 9:00 pm.

If we define the 9:00 am as our t = 0, we have that the maximum, at 3:00pm, is at t = 6 hours.

and the other minimum, at 9:00pm, is at t = 12 hours.

Then we need to find a trigonometric function that has the minimum at t = 0, we can do this as:

-Cos(c*t)

when t = 0

-cos(0) = - 1

then we have a function:

C(t) = -A*cos(c*t) + B

where A, c and B are constants.

We know that at t = 0 we have 0 customers, and that at t = 6h we have 875 customers, that is the maximum.

then:

C(0) = 0 = -A + B

this means that A  = B, then our function is:

C(0) = -A*cos(c*t) + A.

now, at t = 6h we have a maximum, this means that -A*cos(c*6h) = A

then:

C(6h) = A + A = 875

2A = 875

A = 875/2 = 437.5

and we also have that, if -cos(c*6) = 1

then cos(c*6) = -1

and we know that cos(pi) = -1

then c*6 = pi

c = pi/6

Then our function is

C(t) = -475.5*cos(t*pi/6) + 475.5

8 0
3 years ago
In a manufacturing process that laminates several ceramic layers, 1% of the assembles are defective. Assume that the assemblies
Setler79 [48]
There are several information's already given in the question. based on those information's, the answer can be easily deduced.

a. It is already given that 1% are defective. It is required to find the number that is needed to be checked to get 5 defective products.
Then
1% of X = 5
0.01X = 5
x = 5/0.01
   = 500

b. <span>σ = square root [(<span><span><span><span>n^2</span>−1)/</span>12]
       = square root [(250000 - 1)/12]
       = square root [249999/12]
       = square root (20833.25)
       = 144.34
       = 144
I hope the procedure is clear enough for you to understand. I also hope that this is the answer that you were looking for and the answer has actually come to your desired help.</span></span></span>
6 0
3 years ago
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