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Mars2501 [29]
3 years ago
14

What is 52 divided by 2? please help meeeee A. 16 B. 26 C. 27 D. 36

Mathematics
2 answers:
Alisiya [41]3 years ago
8 0

Answer:

B. 26

Step-by-step explanation:

Lapatulllka [165]3 years ago
6 0

Answer:

D. 26

Step-by-step explanation:

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3 years ago
What is the simplified form of this expression? (8x − 7) + (-2x − 9) − (4x − 3)
Murljashka [212]

Answer:

The answer to your question is:         2x -13

Step-by-step explanation:

         Simplified                             (8x − 7) + (-2x − 9) − (4x − 3)

                                                       8x - 7 - 2x - 9 - 4x + 3

         Simplified like terms            8x - 2x - 4x - 7 - 9 + 3

                                                       2x -13                                                        

4 0
3 years ago
Read 2 more answers
If Professor Wilson found that the test scores of his students had a variance of 4.4, what is the standard deviation? Type a num
malfutka [58]

Answer:

The standard deviation will be: 2.1        

Step-by-step explanation:

We know that standard deviation is basically the square root of variance.

Using the formula to calculate the standard deviation

s=\sqrt{s^2}

As

  • The variance =  s² = 4.4

so the standard deviation can be calculated as:

standard deviation =\sqrt{s^2}

                                 =\sqrt{\left(4.4\right)^}

                                  =2.1

Therefore, the standard deviation will be: 2.1                      

8 0
3 years ago
What is 1/5 expressed as a percent? A. 10% B. 20% C. 30% D. 50%
Serggg [28]

Answer:

I'm pretty sure it's B.20%

8 0
3 years ago
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Determine (without solving the problem) an interval in which the solution of the given initial value problem is certain to exist
yuradex [85]

Answer:

0 < t < 5 is the required interval for the differential equation (t - 5)y' + (ln t)y = 6t to have a solution.

Step-by-step explanation:

Given the differential equation

(t - 5)y' + (ln t)y = 6t

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We can rewrite the differential equation by dividing it by (t - 5) as

y' + [(ln t)/(t - 5)]y = 6t/(t - 5)

(ln t)/(t - 5) is continuous on the interval (0, 5) and (5, +infinity).

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We see that for these expressions, we have continuity at the intervals (0, 5) and (5, +infinity).

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The solution to differential equation is certain to exist at (0, 5)

Which implies that

0 < t < 5

is the required interval.

3 0
3 years ago
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