1 km/hr = 1000/3600 m/s = 5/18 m/s
time taken = 5 x 18/5 sec = 18 sec
The surface is frictionless, so there is no frictional force acting on the ball. There are no other forces acting on the ball in the horizontal direction, so it's a uniform motion with constant speed. Therefore, the velocity of the ball will remain the same for the entire duration of the motion, and so after 5 seconds the velocity is still 15 m/s.
Answer:
altitude of satellite from earth surface is 7140 km
Explanation:
given data:
mass of satellite = 5000kg
altitude of satellite from earth surface can be calculated by using given relation
where,
p - satellite's period in seconds,
a - satellite's altitude in meters,
G - gravitational constant (6.67 x 10^-11 m³/kgs²) and
M - mass of Earth 5.98 x 10^24 kg
solving for altitude we have
a = 7,138,000 meters = 7,140 km
altitude of satellite from earth surface is 7140 km