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denis-greek [22]
3 years ago
11

Say you have a differential drive robot that has an axle length of 30cm and wheel diameter of 10cm. Find the angular velocity fo

r the left and right wheel if the robot is going to a. Spin in place at a rate of 6 rpm (revolutions per min), b. Drive a circle of radius 1 meter (measured center of circle to middle of axle) at 3 rpm, c. Drive a straight line at 1 meter/min.
Physics
1 answer:
Klio2033 [76]3 years ago
8 0

Answer:

a) ω1 = 18rpm    ω2 = -18rpm

b) ω1 = 102rpm     ω2 = 138rpm

c) ω1 = ω2 = 3.18rpm

Explanation:

For the first case, we know that each wheel will spin in a different direction but with the same magnitude, so:

ωr = 6rpm   This is the angular velocity of the robot

\omega = \frac{\omega r * D/2}{r_{wheel}}  where D is 30cm and rwheel is 5cm

\omega = \frac{6 * 30/2}{5}=18rpm  One velocity will be positive and the other will be negative:

ω1 = 18rpm    ω2 = -18rpm

For part b, the formula is the same but distances change. Rcircle=100cm:

\omega 1 = \frac{\omega r * (R_{circle} - D/2)}{r_{wheel}}

\omega 2 = \frac{\omega r * (R_{circle} + D/2)}{r_{wheel}}

Replacing values, we get:

\omega 1 = \frac{6 * (100 - 30/2)}{5}=102rpm

\omega 2 = \frac{\omega r * (100 + 30/2)}{5}=138rpm

For part c, both wheels must have the same velocity:

\omega = \frac{V_{robot}}{r_{wheel}}=20rad/min

\omega = 20rad/min * \frac{1rev}{2*\pi rad}=3.18rpm

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Answer:

Answer D : about 1067 meters

Explanation:

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