This equation is one of the most useful in classical physics. It is a concise statement of Isaac Newton's<span> Second Law of Motion, holding both the proportions and vectors of the Second Law. It translates as: The net force on an object is </span>equal<span> to the </span>mass<span>of the object multiplied by the </span>acceleration<span> of the object.</span>
<u>Answer:</u>
<em>The outside edge of a spinning compact disc moves with a higher velocity than the inner track of the disc.</em>
<u>Explanation:</u>
Here the compact disc undergoes rotational motion about a fixed axis which is its centre in this case. The particles in rotational motion have angular velocity which is given by the equation
ω = ∅/t
Where θ is the angular displacement and t is the time.
The transnational speed of a particle which is in circular motion is given by the equation
v = rω
r is the distance of the point from the rotation centre
The transnational speed of the particles is merely determined by their distance from the centre in this case. It is due to the equality of angular velocity of all the points.
The distance of the outer edge of the compact disc from its rotational centre is larger than the distance of inner edge from the rotational centre. Thus the farther edge of a spinning disc moves faster than the nearer edge.
Answer:
<h3>40.0 Joules. None of the answers is correct</h3>
Explanation:
Kinetic energy of an object is expressed as;
KE = 1/2mv² where;
m is the mass of the object
V is the velocity of the object.
Let Ma be the mass of the basketball and Mb be the mass of baseball.
If the mass of the basketball shown below is 4 times the mass of the baseball, then Ma = 4Mb
KE of the basket ball = 1/2MaVa²
Va² = 2(KE)a/Ma ...... 1
KE of the baseball = 1/2MbVb²
Vb² = 2(KE)b/Mb .......... 2
Since their velocities are the same, hence Va²= Vb²
2(KE)a/Ma = 2(KE)b/Mb
Substituting Ma = 4Mb into the resulting expression.
2(KE)a/4Mb = 2(KE)b/Mb
2(KE)a/4 = 2(KE)b
Given Kinetic energy of baseball (KE)b = 10.0J, the expression becomes;
2(KE)a/4 = 2(10)
2(KE)a = 4*20
2(KE)a = 80
(KE)a = 80/2
(KE)a = 40.0J
Hence the kinetic energy of the basketball is 40.0Joules