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shtirl [24]
3 years ago
5

Which of the following would be a reasonable experimental strategy to prevent translation of a particular prokaryotic mRNA witho

ut targeting the ribosome? Which of the following would be a reasonable experimental strategy to prevent translation of a particular prokaryotic mRNA without targeting the ribosome? Inhibit termination factors. Inhibit the sigma factor. Add suppressor tRNA molecules to the cell. Mutate or remove the Shine-Dalgarno sequence on the mRNA.
Biology
1 answer:
nika2105 [10]3 years ago
4 0

Answer:

The correct answer is "Mutate or remove the Shine-Dalgarno sequence on the mRNA".

Explanation:

The Shine-Delgarno sequence is a fragment of bacterial and archaeal messenger RNA that helps to recruit the messenger RNA to the ribosome to initiate protein synthesis by translation. Mutating  or removing the Shine-Dalgarno sequence on the mRNA will prevent translation of a particular prokaryotic mRNA. Therefore, this is a reasonable experimental strategy to achieve this effect without targeting the ribosome, but the prokaryotic mRNA.

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In man, two abnormal conditions, cataracts (C) in the eyes and excessive fragility (F) in the bones, seem to depend on separate
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Complete question:

In man, two abnormal conditions, cataracts (C) in the eyes and excessive fragility (F) in the bones, seem to depend on separate dominant genes located on different chromosomes.  Normal vision and normal bones are recessive traits.  A man with cataracts and normal bones, whose father had normal eyes, married a woman free from cataracts but with fragile bones.  Her father had normal bones.  

1. What is the genotype of the man with cataracts and normal bones?

2. What is the genotype of the woman with normal vision and fragile bones?

3. What type of offspring might this couple expect?

Answer:

  1. Cc ff
  2. cc Ff  
  3. F1)  4/16 = 1/2 = 25% CcFf, cataracts and fragile bones

              4/16 = 1/2 = 25% Ccff, cataracts and normal bones

              4/16 = 1/2 = 25% ccFf, normal eyes and fragile bones

              4/16 = 1/2 = 25% ccff normal eyes, normal bones

Explanation:

Due to technical problems, you will find the complete answer and explanation in the attached files

Download pdf
3 0
3 years ago
Seed size in a plant is a polygenic characteristic. A grower crosses two pure-breeding varieties of the plant and measures seed
Juli2301 [7.4K]

Answer:

The F1 progeny is completely heterozygous for the <em>loci</em> of interest since they were obtained by mating between two pure-breeding plant lines. In the next generation, the backcross progeny will have homo-zygous individuals and therefore they will be more variable, resulting from meiosis in F1 hybrids

Explanation:

An F1 resulting from the cross between two pure-breeding plant lines will produce all hybrid individuals, all of them genetically (and phenotypically) identical. Meiosis in F1 hybrids is well known to produce homo-zygous genotypes and thus increases genetic diversity in progeny. For instance, for a single <em>locus</em>, the expected ratio of genotypes obtained from crossing two heterozygous parents is 1:2:1, i.e., one homo-zigous dominant individual, two heterozygous individuals (genetically identical to the parents) and one homo-zygous recessive individual; while the expected phenotypic ratio is 3:1 (i.e., 3 dominant expressing: 1 recessive expressing​).

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