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Degger [83]
2 years ago
10

Ayo, here are some points. Also- what's an unpopular opinion you have? About anything.

Mathematics
2 answers:
inessss [21]2 years ago
6 0

Answer:

thx fam

Step-by-step explanation:

spider-man can beat iron man

Sati [7]2 years ago
3 0

Answer:

hli

Step-by-step explanation:

how r u dear hope u r fine

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What is five + five
LekaFEV [45]
Five plus five is ten
6 0
3 years ago
What is the area of the shaded sector
Whitepunk [10]

Answer:

Area = 634.21 square metre

Step-by-step explanation:

Area of shaded region = Area of the circle - Area of the sector

Area \ of \ the \ circle = \pi r^2 = 225 \pi\\\\Area \ of \ the \ sector = \pi r^2 \frac{ \theta}{360} = \pi \times 225 \times \frac{37}{360}

Area \ of \ shaded \ region = 225 \pi - (225 \pi \times  \frac{37}{360})

                                   = 225 \pi (1 - \frac{37}{360})\\\\= 225 \pi \times 0.89722\\\\=634.21 m^2

7 0
3 years ago
Read 2 more answers
Math .. help! asap aleks is so hard
3241004551 [841]
Answer is squareroot of 21 or 4.58 in decimal
by pythagorean theorem



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Mark me as brainliest if you find the solution helpful. thanks
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3 0
3 years ago
Two surveys were independently conducted to estimate a population mean, μ. denote the estimates and their standard errors by x1
lyudmila [28]

Hi there what you need is lagrange multipliers for constrained minimisation. It works like this,

V(X)=α2σ2X¯1+β2\sigma2X¯2

Now we want to minimise this subject to α+β=1 or α−β−1=0.

We proceed by writing a function of alpha and beta (the paramters you want to change to minimse the variance of X, but we also introduce another parameter that multiplies the sum to zero constraint. Thus we want to minimise

f(α,β,λ)=α2σ2X¯1+β2σ2X¯2+λ(\alpha−β−1).

We partially differentiate this function w.r.t each parameter and set each partial derivative equal to zero. This gives;

∂f∂α=2ασ2X¯1+λ=0

∂f∂β=2βσ2X¯2+λ=0

∂f∂λ=α+β−1=0

Setting the first two partial derivatives equal we get

α=βσ2X¯2σ2X¯1

Substituting 1−α into this expression for beta and re-arranging for alpha gives the result for alpha. Repeating the same steps but isolating beta gives the beta result.

Lagrange multipliers and constrained minimisation crop up often in stats problems. I hope this helps!And gosh that was a lot to type!xd

3 0
3 years ago
Solve y=f(x) for x then find the input when the output is 6 <br><br> f(x)=x+9
r-ruslan [8.4K]

x = -3

So to figure this out we can readjust the equation to make it easier to solve

f(x) = x + 9 is equal to x+9 = 6

From here we can just subtract 9 from both sides and we get our answer!

x+(9-9) = (6-9)\\x = -3

4 0
3 years ago
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