Answer:
<h3> (x-8)²+(y-3)² = 81</h3>
Step-by-step explanation:
The general equation of a circle is expressed as;
(x-a)²+(y-b)² = r² where;
(a, b) is the centre of the circle
r is the radius
Given the centre (8, 3) and the radius of 9, the equation of the circle will be;
(x-a)²+(y-b)² = r²
(x-8)²+(y-3)² = 9²
(x-8)²+(y-3)² = 81
hence the required equation is (x-8)²+(y-3)² = 81
Hi. You have to do trial and error with each of the choices to see which of those apply. They are points on the given function y=22x+32 that lie on point (x,y). Just substitute the x-and y values to the function.
a. (10,480) => x = 10, y = 480
y = 480 = 22(10) + 32
480 = 252 (does not apply)
b. (5,142) => x = 5, y = 142
y = 142= 22(5) + 32
142 = 142 (apply)
c. (8,208) => x = 8, y = 208
y = 208 = 22(8) + 32
208 = 208 (apply)
d. (7,154) => x = 7, y = 154
y = 154 = 22(7) + 32
154 = 186 (does not apply)
The answer is B and C.
Definitely not. They are both perfect squares. A prime number is one where its only factors are one and itself.
15*15=225. There's only one square root of 225... there's only one square root of any number ...
Answer:
x2 + x – 2=4x
sorry if i give you the wrong answer
Step-by-step explanation:
