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3 years ago

How do I do this problem?

Mathematics

2 answers:

lions [1.4K]3 years ago

5 0

Answer:

hey you can use scan and search

hram777 [196]3 years ago

3 0

Answer:

I got : 0.42264973

Step-by-step explanation:

1/ -√3 + 1

-√3 = -1.73 ( 2 decimal place )

1/ -1.73 + 1

and found the answer

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Select the type of equations Consistent Equivalent Inconsistent

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Answer:

21 is the answer for that

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3 years ago

Residents of the 50 most populous metropolitan statistical areas in the United States listed ____ as one of cities where they fe

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Answer:

fifty dollors a night

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2 years ago

Suppose that there are two types of tickets to a show: advance and same-day. Advance tickets cost $35 and same-day tickets $30 c

Marina CMI [18]

Answer:

The number of same-day tickets sold is 15

The number of advance ticket sold is 20

Step-by-step explanation:

Given as :

The cost of each Advance ticket = $35

The cost of each same-day ticket = $30

The total cost of the tickets sold = $1150

The total number of tickets sold = 35

Let The number of advance ticket sold = a

And The number of same-day ticket sold = s

Now, According to question

The total number of tickets sold =The number of advance ticket sold + The number of same-day ticket sold

I.e a + s = 35 .....A

The total number of tickets sold = The cost of each Advance ticket × The number of advance ticket sold + The cost of each same-day ticket × The number of same-day ticket sold

I.e $35 a + $30 s = $1150

or, 35 a + 30 s = 1150 .......B

Now, solving eq A and B

35 × ( a + s) - ( 35 a + 30 s ) = 35 × 35 - 1150

or, ( 35 a - 35 a ) + ( 35 s - 30 s ) = 1225 - 1150

or, 0 + 5 s = 75

∴ s = $\frac{75}{5}$

I.e s = 15

So, The number of same-day tickets sold = s = 15

Put the value of s in Eq A

So, a + 15 = 35

∴ a = 35 - 15

I.e a = 20

So, The number of advance ticket sold = a = 20

Hence The number of same-day tickets sold is 15

And The number of advance ticket sold is 20 Answer

7 0

3 years ago

The average THC content of marijuana sold on the street is 9.3%. Suppose the THC content is normally distributed with standard d

velikii [3]

Answer:

a) $X \sim N(9.3,1)$

b) $P(X>9.2)=P(\frac{X-\mu}{\sigma}>\frac{9.2-\mu}{\sigma})=P(Z>\frac{9.2-9.3}{1})=1-P(Z$

c) The value of height that separates the bottom 75% of data from the top 25% is 9.9745.

Step-by-step explanation:

1) Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

2) Part a

Let X the random variable that represent the heights of a population, and for this case we know the distribution for X is given by:

$X \sim N(9.3,1)$

Where $\mu=9.3$ and $\sigma=1$

3) Part b

We are interested on this probability

$P(X>9.2)$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

If we apply this formula to our probability we got this:

$P(X>9.2)=P(\frac{X-\mu}{\sigma}>\frac{9.2-\mu}{\sigma})=P(Z>\frac{9.2-9.3}{1})=1-P(Z$

4) Part c

For this part we want to find a value a, such that we satisfy this condition:

$P(X>a)=0.25$ (a)

$P(X$ (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.

As we can see on the figure attached the z value that satisfy the condition with 0.75 of the area on the left and 0.25 of the area on the right it's z=0.6745. On this case P(Z<0.6745)=0.75 and P(z>0.6745)=0.25

If we use condition (b) from previous we have this:

$P(X$