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Soloha48 [4]
3 years ago
14

Please solve this

a1" title=" |x ^{2} + 3x - 1 | < 3" alt=" |x ^{2} + 3x - 1 | < 3" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
klasskru [66]3 years ago
8 0
\bf |x^2+3x-1|\ \textless \ 3\implies &#10;\begin{cases}&#10;+(x^2+3x-1)\ \textless \ 3\\\\&#10;-(x^2+3x-1)\ \textless \ 3&#10;\end{cases}\\\\&#10;-------------------------------\\\\&#10;x^2+3x-1\ \textless \ 3\implies x^2+3x-4\ \textless \ 0\implies (x+4)(x-1)\ \textless \ 0&#10;\\\\\\&#10;x\ \textless \ &#10;\begin{cases}&#10;-4\\&#10;1&#10;\end{cases}\\\\&#10;-------------------------------\\\\&#10;-(x^2+3x-1)\ \textless \ 3\implies x^2+3x-1\boxed{\ \textgreater \ }-3&#10;\\\\\\&#10;x^2+3+2\ \textgreater \ 0\implies (x+2)(x+1)\ \textgreater \ 0\implies x\ \textgreater \ &#10;\begin{cases}&#10;-2\\&#10;-1&#10;\end{cases}
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Please please help me! all you smart math people please give me a hand​
Step2247 [10]

Answer:

Step-by-step explanation:

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5 0
2 years ago
168 h = [?] days helppp
Nitella [24]

24 h in 1 day

just divide the hours by 24

168 : 24 = 7

6 0
2 years ago
Using the function attached.<br> Find (f+G)(x)
sp2606 [1]

We have been given two functions f(x)=-8x^3+5x^2+7x+4 and g(x)=8x^3-2x+3. We are asked to find (f+g)(x).

We will use composite function property (f+g)(x)=f(x)+g(x) to solve our given problem.

(f+g)(x)=-8x^3+5x^2+7x+4+8x^3-2x+3  

Now we will combine like terms as:

(f+g)(x)=-8x^3+8x^3+5x^2+7x-2x+4+3

(f+g)(x)=5x^2+5x+7

Therefore, the value of  (f+g)(x) would be 5x^2+5x+7.

8 0
3 years ago
James folds a piece of paper in half several times,each time unfolding the paper to count how many equal parts he sees. After fo
Snezhnost [94]

Answer:

There will be total 2048 parts of the given paper if James if able to fold the paper eleven times.

The needed function is y = 2 ^n

Step-by-step explanation:

Let us assume the piece of paper James decides to fold is a SQUARE.

Now, let us assume:

n : the number of times the paper is folded.

y : The number of parts obtained after folds.

Now, if the paper if folded ONCE ⇒  n = 1

Also, when the pap er is folded once, the parts obtained are TWO equal parts.

⇒  for n = 1 , y = 2       ..... (1)

Similarly, if the paper if folded TWICE  ⇒  n = 2

Also, when the paper is folded twice, the parts obtained are FOUR equal parts.

⇒  for n = 2 , y = 4       ..... (2)

⇒y  = 2^2  =  2^n

Continuing the same way, if the paper is folded SEVEN times  ⇒  n = 7

So, y = 2^ n = 2^7 = 128

⇒  There are total 128 equal parts.

Lastly,  if the paper is folded ELEVEN  times  ⇒  n = 11

So, y = 2^ n = 2^{11} = 2048

⇒  There are total 2048 equal parts.

Hence, there will be total 2048 parts of the given paper if James if able to fold the paper eleven times.

And the needed function is y = 2 ^n

8 0
3 years ago
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san4es73 [151]

Answer:

1. D

2. A

I think that is the answer

5 0
2 years ago
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