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2 years ago

Find x for brainiest

Mathematics

2 answers:

anastassius [24]2 years ago

8 0

Answer:

x=36

Step-by-step explanation:

These angles added together equal 180 degrees

2x + 3x =180

5x = 180

x = 36

olga55 [171]2 years ago

7 0

Answer:

x = 36

Step-by-step explanation:

2x and 3x are supplementary angles they both add up to 180 degree Therefore 2x + 3x = 180 5x = 180 180/5 = x x = 36

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Are two equilateral triangles always equal

weqwewe [10]

No not always the degrees maybe
i hope this helps

6 0

2 years ago

Read 2 more answers

Please help! will give 30 points!

insens350 [35]

Answer:

Other needs =25,2 degrees

insurance = 100,8 degrees

Taxes= 7,2

Housing = 57,6

food= 57,6

childcare = 64,8

transportation = 46,8

Step-by-step explanation:

Its % of 360 degrees so you have to calculate the percentage of each categorie on 360 degrees to find the angles. Exemple, for the Other needs, you take 7% out of 360 degrees and you find that it is equal to 25,2. (7% x360 degrees /100)

7 0

2 years ago

Find the equation of the sphere if one of its diameters has endpoints (4, 2, -9) and (6, 6, -3) which has been normalized so tha

Pavel [41]

Answer:

$(x - 5)^2 + (y - 4)^2 + (z - 6)^2 = 14$ .

(Expand to obtain an equivalent expression for the sphere: $x^2 - 10\,x + y^2 - 8\, y + z^2 - 12\, z + 63 = 0$ )

Step-by-step explanation:

Apply the Pythagorean Theorem to find the distance between these two endpoints:

$\begin{aligned}&\text{Distance}\cr &= \sqrt{\left(x_2 - x_1\right)^2 + \left(y_2 - y_1\right)^2 + \left(z_2 - z_1\right)^2} \cr &= \sqrt{(6 - 4)^2 + (6 - 2)^2 + ((-3) - (-9))^2 \cr &= \sqrt{56}}\end{aligned}$ .

Since the two endpoints form a diameter of the sphere, the distance between them would be equal to the diameter of the sphere. The radius of a sphere is one-half of its diameter. In this case, that would be equal to:

$\begin{aligned} r &= \frac{1}{2} \, \sqrt{56} \cr &= \sqrt{\left(\frac{1}{2}\right)^2 \times 56} \cr &= \sqrt{\frac{1}{4} \times 56} \cr &= \sqrt{14} \end{aligned}$ .

In a sphere, the midpoint of every diameter would be the center of the sphere. Each component of the midpoint of a segment (such as the diameter in this question) is equal to the arithmetic mean of that component of the two endpoints. In other words, the midpoint of a segment between $\left(x_1, \, y_1, \, z_1\right)$ and $\left(x_2, \, y_2, \, z_2\right)$ would be:

$\displaystyle \left(\frac{x_1 + x_2}{2},\, \frac{y_1 + y_2}{2}, \, \frac{z_1 + z_2}{2}\right)$ .

In this case, the midpoint of the diameter, which is the same as the center of the sphere, would be at:

$\begin{aligned}&\left(\frac{x_1 + x_2}{2},\, \frac{y_1 + y_2}{2}, \, \frac{z_1 + z_2}{2}\right) \cr &= \left(\frac{4 + 6}{2},\, \frac{2 + 6}{2}, \, \frac{(-9) + (-3)}{2}\right) \cr &= (5,\, 4\, -6)\end{aligned}$ .