I think it’s C. Because
X ≤ 9and 9 is higher than -7 (sorry if I’m wrong)
Solution :
Demand for cola : 100 – 34x + 5y
Demand for cola : 50 + 3x – 16y
Therefore, total revenue :
x(100 – 34x + 5y) + y(50 + 3x – 16y)
R(x,y) = 

In order to maximize the revenue, set



.............(i)


.............(ii)
Solving (i) and (ii),
4 x (i) ⇒ 272x - 32y = 400
(ii) ⇒ (-<u>) 8x - 32y = -50 </u>
264x = 450
∴ 

So, x ≈ $ 1.70 and y = $ 1.99
R(1.70, 1.99) = $ 134.94
Thus, 1.70 dollars per cola
1.99 dollars per iced ted to maximize the revenue.
Maximum revenue = $ 134.94
Answer:
Yes
Step-by-step explanation:
<u>7^2 + 4x</u>:
Fill in for x :
7^2+4(2)
solve:
49+8
=57
<u>4x+(7 x 7)</u>:
Fill in for x:
4(2) + (7 x 7)
solve:
8+49
=57
Thus, the correct answer is yes
Option 3 is the correct one
Answer:
1.2
Step-by-step explanation:
3q+3.97=7.57
3q=7.57-3.97
3q=3.6
q=3.6/3
q=1.2