Michael took the return trip at a velocity 33.75 miles per hour.
<h3>How fast did Michael drive in his return trip?</h3>
Let suppose that Michael drove in <em>straight line</em> road and at <em>constant</em> velocity. Therefore, the speed of the vehicle (v), in miles per hour, can be defined as distance traveled by the vehicle (d), in miles, divided by travel time (t), in hours.
First trip
45 = s / 3 (1)
Second trip
v = s / 4 (2)
By (1) and (2):
45 · 3 = 4 · v
v = 33.75 mi / h
Michael took the return trip at a velocity 33.75 miles per hour.
To learn more on velocities: brainly.com/question/18084516
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1) x= -7
2) x= -5
3) x=-22
4) x =8
Not sure about the last one tho
I tried to help :)
E and B are your answers to this
Answer:
14.5 × 3.18 - 14.5 x 1.88
You paid $18.85 more in june than in February
Step-by-step explanation:
In order to find the answer to this question you will need to find how much you paid in June and how much you paid in February.
ex.14.5 x 3.18 - 14.5 x 1.88
To solve this you need to find the product of 14.5 x 3.18 and 14.5 x 1.88 and then subtract them from eachother.
ex.14.5 x 3.18 =46.11
14.5 x 1.88=27.26
46.11-27.26=18.85
