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snow_tiger [21]
2 years ago
6

Please help I’ll give 10 points

Computers and Technology
1 answer:
yaroslaw [1]2 years ago
5 0

Answer: Do

Explanation:

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Which one bc im struggling
Setler79 [48]

Answer:

cant really see it

Explanation:

3 0
3 years ago
Write a program that convert a temperature in Fahrenheit to the equivalent temperature in Celsius. The initial temperature in Fa
baherus [9]

<u>Answer:</u>

//import the necessary class

import java.util.Scanner;

//Begin class definition

public class ConvertToCelsius{

   

       //Begin main method

    public static void main(String []args){

       //Create an object of the Scanner class

       Scanner input = new Scanner(System.in);

       

       //Display the aim of the program

       System.out.println("**Program to convert from Fahrenheit to Celsius**");

       

       //Prompt the user to enter the temperature in Fahrenheit

       System.out.println("Please enter temperature in Fahrenheit");

       

       //Receive the user's input

       //And store in the appropriate variable

       double tempF = input.nextDouble();

       

       //Convert the temperature to Celsius using

       //C = (9.0 / 5) * (F - 32)

       //C = temperature in Celsius, F = temperature in Fahrenheit

       double tempC = (9.0 / 5) * (tempF - 32);

       

       //Display the result

      System.out.println("The temperature in degree Celsius is: ");

       System.out.println(tempC);

       

       return;

       

    }    //End of main method

}    //End of class definition

<u>Sample Output</u>

**Program to convert from Fahrenheit to Celsius **

Please enter temperature in Fahrenheit

>> 32

The temperature in degree Celsius is:  

0.0

<u>Explanation</u>:

The above code has been written in Java and it contains comments explaining important lines of the code. Please go through the comment. Snapshots of the program and a sample output have been attached to this response.

5 0
3 years ago
Here is the API for a robot library.
marishachu [46]

Answer:

hi

Explanation:

8 0
3 years ago
Evaluate each condition as to whether it is true or not.
ivann1987 [24]

Answer:

For the first one you have not met those requirements because you are still 16, for the second one you have met those requirements because you can either have a score over 30 (which you have 34) or be a valedictorian

Explanation:

Above

7 0
3 years ago
Suppose the daytime processing load consists of 65% CPU activity and 35% disk activity. Your customers are complaining that the
bekas [8.4K]

Answer:

The answer to this question can be described as follows:

Explanation:

Given data:

Performance of the CPU:  

The Fastest Factor Fraction of Work:

f_1=65 \% \\\\=\frac{65}{100} \\\\ =0.65

Current Feature Speedup:

K_1= 1.5

CPU upgrade=6000

Disk activity:

The quickest part is the proportion of the work performed:

Current Feature Speedup:

k_2=3

Disk upgrade=8000

System speedup formula:

s=\frac{1}{(1-f)+(\frac{f}{k})}

Finding the CPU activity and disk activity by above formula:

CPU activity:

S_{CPU}=\frac{1}{(1-f_1)+(\frac{f_1}{k_1})} \\\\=\frac{1}{(1-0.65)+(\frac{0.65}{1.5})} \\\\=1.276 \%  ...\rightarrow (1) \\

Disk activity:

S_{DISK} = (\frac{1}{(1-f_2)+\frac{f_2}{k_2}}) \\\\ S_{DISK} = (\frac{1}{(1-0.35)+\frac{0.35}{3}}) \\\\ = -0.5\% .... \rightarrow (2)

CPU:

Formula for CPU upgrade:

= \frac{CPU \ upgrade}{S_{CPU}}\\\\= \frac{\$ 6,000}{1.276}\\\\= 4702.19....(3)

DISK:

Formula for DISK upgrade:

=\frac{Disk upgrade} {S_{DISK}}\\\\= \frac{\$ 8000}{-0.5 \% }\\\\= - 16000....(4)

equation (3) and (4),

Thus, for the least money the CPU alternative is the best performance upgrade.

b)

From (3) and (4) result,

The disc choice is therefore the best choice for a quicker system if you ever don't care about the cost.

c)

The break-event point for the upgrades:

=4702.19 x-0.5

= -2351.095

From (2) and (3))

Therefore, when you pay the sum for disc upgrades, all is equal $ -2351.095

4 0
3 years ago
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