Answer:
a. The percentage of vehicles who pass through this construction zone who are exceeding the posted speed limit =90.82%
b. Percentage of vehicles travel through this construction zone with speeds between 50 mph and 55 mph= 2.28%
Step-by-step explanation:
We have to find
a) P(X>40)= 1- P(x=40)
Using the z statistic
Here
x= 40 mph
u= 44mph
σ= 3 mph
z=(40-44)/3=-1.33
From the z-table -1.67 = 0.9082
a) P(X>40)=
Probability exceeding the speed limit = 0.9082 = 90.82%
b) P(50<X<55)
Now
z1 = (50-44)/3 = 2
z2 = (55-44)/3= 3.67
Area for z>3.59 is almost equal to 1
From the z- table we get
P(55 < X < 60) = P((50-44)/3 < z < (55-44)/3)
= P(2 < z < 3.67)
= P(z<3.67) - P(z<2)
= 1 - 0.9772
= 0.0228
or 2.28%
Answer:
I get z = +1.8
x= 79
m= 73;s= 4;z= (x-m)/s= 1.5
hope it helps you
Answer:
10+4x
Step-by-step explanation:
COmbine like terms
(c+8)(c-8)
3(2y+5)(2y-5)
There are no like terms so it's still ab^2-b
Answer:
10%
Step-by-step explanation:
We know Perimeter of rectangle
= 2 (Length + Width)
If width and length are increased by 10%
New length= L + 10/100L = (1.1) L
New width = W + 10/100W = (1.1) W
Perimeter = 2 [(1.1) L + (1.1) W]
Perimeter = 2 (1.1) (L + W)
Perimeter = (2.2) (L + W)
Increase in perimeter = 2.2 (L + W) - 2 (L + W)
The increase in Perimeter = 0.2 (L + W)
Percent increase
= 0.2 (L + W)/2 (L + W) × 100
= 0.2/2 × 100
= 0.1 × 100
= 10%
I hope this helped and if it did, please mark as Brainliest.
