<span>i Ace</span>hello :
let : A(-6,6) B(6,-2)
the center is w((-6+6)/2 , (6-2)/2)....(midel <span>[ AB]
w(0 ,2)
the ridus is : r = AB/2
AB = </span>√(-6-6)²+(6+2)² = √(144+64) =<span>√208/2
</span>an equation in <span>standard form equation of the circle :
</span>(x+0)²+(y-2)² = (√208/2)²=208/4 = 52
Answer:
or 2/3
Step-by-step explanation:
because two flips out of 3 all together is 2/3
Answer:
The answer is c
Step-by-step explanation:
C.88cm
Given
s=16t^2
where
s=distance in feet travelled (downwards) since airborne with zero vertical velocity and zero air-resistance
t=time in seconds after release
Here we're given
s=144 feet
=>
s=144=16t^2
=>
t^2=144/16=9
so
t=3
Ans. after 3 seconds, the object hits the ground 144 ft. below.
Answer:
(2, 10)
Step-by-step explanation:
Making the points on a graph and creating a line between them, you can see the equation to connect the two points is -3x + 16. Then, because the points are 5 units apart horizontally, go to the point that is 4 units left of point T (1/4 of the way between T and S) and that is your point: (2, 10)
I apologize if this is incorrect :)