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2 years ago

{red,blue,yellow} find all of the subsets

Mathematics

1 answer:

Masja [62]2 years ago

3 0

Answer:

An empty subset would still be a subset

{}

Then let's pick one at a time

{red}

{blue}

{yellow}

Then in pairs

{red, blue}

{red, yellow}

{blue, yellow}

and finally, everything goes in!

{red, blue, yellow}

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-41^2

Irina-Kira [14]

Answer:

Step-by-step explanation:

I'm going to take a leap here and say that the -41^2 should be a -41t^2 and that the expression should look like this:

$-41t^2-13t+ 9$

A term is a combination of variables and numbers separated by either a plus or a minus from another combination of variables and numbers. We have 3 terms: -41t^2 is one; -13t is another; 9 is the last. So this is a trinomial.

The degree of a polynomial is equal to the degree of the highest degree'd term. Since the leading term has a power of 2 and that's the highest degree of all the terms, this is a second degree polynomial, or a quadratic, to be more specific.

6 0

4 years ago

Convert the angle to decimal degrees and round to the nearest hundredth of a degree. 59 degrees 28'

mariarad [96]

Answer:

121π cm. Im not sure sorry

Step-by-step explanation:

4 0

4 years ago

Round Ed to the nearthest tenth and answer now question

Vikki [24]

Answer:

$y = 9.1$

Step-by-step explanation:

y can be found using the Law of sines as explained below:

m < Y = 106°

m < X = 58°

WY = x = 8

WX = y = ?

Thus,

$\frac{x}{sin(X)} = \frac{y}{sin(Y)}$

$\frac{8}{sin(58)} = \frac{y}{sin(106)}$

$\frac{8}{0.848} = \frac{y}{0.961}$

Multiply both sides by 0.961 to solve for y

$\frac{8}{0.848}*0.961 = \frac{y}{0.961}*0.961$

$\frac{8*0.961}{0.848} = y$

$\frac{8*0.961}{0.848}*0.961 = y$

$9.07 = y$

$y = 9.1$ (to the nearest tenth)

7 0

3 years ago

Plz help me ASAP plz

Reika [66]

Answer:

Q.1: A

Q.2: B

Step-by-step explanation

6 0

3 years ago

Read 2 more answers

Dose anybody know how to solve this problem

exis [7]

check the transformation template below, hmmm so to get the graph of "y" move to the right by 1 unit, we can simply make C = -1.

$y=\stackrel{A}{1}\log_2(\stackrel{B}{1}x+\stackrel{C}{0})+\stackrel{D}{0}\qquad \qquad y=\stackrel{A}{1}\log_2(\stackrel{B}{1}x+\stackrel{C}{1})+\stackrel{D}{0} \implies y=\log_2(x-1)$

now, the x-intercept is simply where the graph touches the x-axis, and when that happens y = 0, so

$\begin{array}{llll} \textit{Logarithm Cancellation Rules} \\\\ log_a a^x = x\qquad \qquad a^{log_a x}=x\leftarrow \textit{let's use this rule} \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \stackrel{y}{0}~~ = ~~\log_2(x-1)\implies 2^0=2^{\log_2(x-1)}\implies 2^0=x-1 \\\\\\ 1=x-1\implies 2=x~\hspace{10em}\stackrel{x-intercept}{(2~~,~~0)}$

6 0

2 years ago