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dybincka [34]
3 years ago
6

What is the z-score of a value that is 2.08 standard deviations greater than the mean?

Mathematics
1 answer:
Nuetrik [128]3 years ago
6 0
The question is asking to states the value of the z-score of a value that is 2.08 standard deviations greater than the mean and base on my research, the possible answer would be z-score is the number of standard deviations above the mean. <span>If you are 5 standard deviations above the mean, that is defined as z = 5. </span><span>If you are 1.1 standard deviations above the mean, that is defined as z = 1.1. </span>
<span>And so if you are 2.08 standard deviations above the mean</span>
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Step-by-step explanation:


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Let x represent the number of batteries and y represent the cost of the batteries. A package of 8 rechargeable batteries costs $
Rasek [7]

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Step-by-step explanation:

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2 years ago
The usher at a wedding asked each of the 80 guests whether they were a friend of the bride or of the groom. Find the probability
yawa3891 [41]

<u>Complete Question</u>

The usher at a wedding asked each of the 80 guests whether they were a friend of the bride or of the groom. The results are: 59 for Bride, 50 for Groom, 30 for both. Find the probability that a randomly selected person from this sample was a friend of the bride OR of the groom.

Answer:

0.9875

Step-by-step explanation:

Total Number of Guests which forms the Sample Space, n(S)=80

Let the Event (a friend of the bride) =A

Let the Event (a friend of the groom) =B

n(A) =59

n(B)=50

Friends of both bride and groom, n(A \cap B)=30

Therefore:

n(A \cup B)=n(A)+n(B)-n(A \cap B)\\n(A \cup B)=59+50-30\\n(A \cup B)=79

The number of Guests who was a friend of the bride OR of the groom = 79

Therefore:

The probability that a randomly selected person from this sample was a friend of the bride OR of the groom.

P(A \cup B) =\dfrac{n(A \cup B) }{n(S)} \\\\=\dfrac{79 }{80}\\\\=0.9875

4 0
3 years ago
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