Let f be amount of 43% and s be amount of 16%...
s+f=90, f=90-s
(.16s+.43f)/90=.25 using f found above we get:
(.16s+.43(90-s))/90=.25
.16s+38.7-.43s=22.5
-.27s=-16.2
s=60, and since f=90-s, f=30
So the chemist will need to mix 60ml of 16% solution with 30ml of 43% solution to create 90ml of a 25% solution.
What is the answer to this problem im stuck on this one too
Collection of Chase = 27.34
Collection of Sydney = 9.83+27.34 = 37.17
Let ally's collection be = x
As Ally collects 4 times as much as Sydney so,
x= 4*(37.17) =148.68
Hence, Ally collects 148.68 units
Answer:
5r^2+2
Step-by-step explanation:
(4r^2 – 3r + 2) – (-r^2 – 3r) =
Distribute the minus sign
(4r^2 – 3r + 2) +r^2 + 3r =
Combine like terms
(4r^2 + r^2 – 3r+ 3r + 2) =
5r^2+2