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blagie [28]
3 years ago
5

What are the values of m and n

Mathematics
2 answers:
Nikitich [7]3 years ago
3 0

Answer:

  • m = 20°, n = 45°

Step-by-step explanation:

Both of the triangles are isosceles as marked on the diagram.

<u>The right triangle has missing angles of:</u>

  • n = 90°/2 = 45°

<u>The missing angles of the bigger triangle:</u>

  • m + n = 1/2(180° - 50°)
  • m + 45° = 65°
  • m = 20°
aksik [14]3 years ago
3 0

<u><em>Answer:</em></u>

<u><em>m = 20°</em></u>

<u><em>n = 45°</em></u>

<u><em /></u>

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Find the angle between the hands of a clock at 5:15<br><br> A 60<br> B 67.5<br> C 75
Viktor [21]

Answer:

Option B is correct.

67.5 degree

Step-by-step explanation:

To find the angle between the hands of a clock.

Given that:

Hands of a clock at 5 : 15.

We know that:

A clock is a circle and it always contains 360 degree.

Since, there are 60 minutes on a clock.

\frac{360^{\circ}}{60 minutes} = 6^{\circ} per minutes

so,  each minute is 6 degree.

The minutes hand on the clock will point at 15 minute,

then, its position on the clock is:

(15) \cdot 6^{\circ} = 90^{\circ}

Also, there are 12 hours on the clock

⇒Each hour is 30 degree.

Now, can calculate where the hour hand at 5:00 clock.

⇒5 \cdot 30 =150^{\circ}

Since, the hours hand is between 5 and 6 and we are looking for 5:15 then :

15 minutes is equal to \frac{1}{4} of an hour

⇒150+\frac{1}{4}(30) = 150+7.5 = 157.5^{\circ}

Then the angle between two hands of clock:

⇒\theta = 150.75 -90 = 67.5^{\circ}

Therefore, the angle between the hands of a clock at 5: 15 is: 67.5 degree.

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3 years ago
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Ede4ka [16]

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Step-by-step explanation:

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Describe two to evaluate 37% of the sum of 27 and 3/5 and 15.9
zhuklara [117]
First way is to first find the sum and then find 37% of it. Second way is another way round, find 37 of 27 3/5 and 37% of 15.9 and then add it.

Lets do it
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Second way its
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3 years ago
(Hehe...Please ignore the markings)
inysia [295]

Answer:

See below:

Step-by-step explanation:

Problem 1:

Multiply Equation 1 by 4, keep Equation 2 the same.

x+y=8, multiply each term by 4:

4*x=4x, 4*y=4y, 8*4=32

so, the equivalent system is: 4x+4y=32 and x-y=2

Solve the system of equations:

x-y=2 becomes x=y+2

plug into 4x+4y=32 to solve for y

4(y+2)+4y=32---> 4y+8+4y=32--->8y=24---> y=3

Plug into x-y=2---> x-3=2---> x=5

Problem 1 Answer:

Equivalent system: 4x+4y=32, x-y=2; solution: x=5, y=3

Problem 2:

Keep Equation 1 the same. Add 1 and 2.

To add an equation, add the left sides together, and then the rights.

so: x+y=8 + x-y=2 gives us: 2x=10

solve for x ---> 2x/2=10/2--->x=5

plug x into x+y=8--->5+y=8--->y=3

Problem 2 answer:

Equivalent system: x+y=8, 2x=10; solution:x=5, y=3

Problem 3:

Subtract Equation 2 from 1, and keep 2 the same.

To subtract an equation, subtract the left sides, then the rights. We are subtracting 1<em> from </em>2, so its 2-1.

x-y=2 - x+y=8 gives us: -2y=-6

Solve for y by dividing by -2-->-2y/-2=-6/-2---> y=3

Plug into x-y=2---> x-3=2---> x=5

Problem 3 answer:

Equivalent system: -2y=-6, x-y=2; solution: x=5, y=3

Problem 4:

Multiply the sum of Equation 1 and 2 by a factor of 3. Keep equation 2 the same.

First we add 1 and 2: (we did this earlier) ---> 2x=10 ---> now we multiply it all by 3---> 2x*(3)=10*(3)---> this gives us: 6x=30---> now divide by 6 to solve for x: 6x/6=30/6 gives us: x=5

Now, solve for y by plugging x into equation 2: x-y=2---> 5-y=2--->y=3

Problem 4 answer:

Equivalent system: 6x=30, x-y=2; solution: x=5, y=3

______

Quick Tip: One thing inherent of Equivalent systems is that they have the same set of solutions. Thus, we know the systems are equivalent when they have the same set of solutions for x and y. Moreover, you don't need to solve every time after you attempt to find an equivalent system, instead, just plug in the values found in problem 1 to each new set of equations to test if they are equivalent.

If we find x=5 and y=3 for x+y=8 and x-y=2, then all we have to do is plug them in to 6x=30 and -2y=-6 to see if they are equivalent.

6(5)=30 ---> true

-2(3)=-6 ---> true

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Answer:

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