Answer:
30
Step-by-step explanation:
because 6 × 5 equals 30 and when you're looking for when something's going to be the same you got to do what your numbers are times each other
9514 1404 393
Answer:
(6,2)
Step-by-step explanation:
As is often the case with multiple-choice problems, you don't actually need to know the detailed working. You just need to know what the answer looks like.
When point X is dilated by a factor of 2 with point Z as the center of dilation, it will move to a location twice as far from Z. You can tell by looking at the graph that X' will be in the first quadrant, above and to the right of the location of X. The only sensible answer choice is ...
X' = (6, 2)
_____
<em>Additional comment</em>
X is a distance of X-Z = (4, 0) -(2, -2) = (2, 2) from Z Doubling that will put the image point a distance of 2(2, 2) = (4, 4) from Z. When this is added to Z, we find ...
X' = Z + (4, 4) = (2+4, -2+4) = (6, 2)
Answer:
1. 500
2. 2,286
Step-by-step explanation:
1. $250 divide by 0.5
2. 762 times by 3
Answer:
339.3 cm. squared
Step-by-step explanation:
Answer:
The calculation in step 3 is wrong
Step-by-step explanation:
1) The mean of a dataset is given by the sum of the values of the dataset divided by the number of values.
In this problem, the dataset is
35, 16, 23, 42, 19
And the number of data is
N = 5
So the mean is
![\bar x=\frac{35+16+23+42+19}{5}=27](https://tex.z-dn.net/?f=%5Cbar%20x%3D%5Cfrac%7B35%2B16%2B23%2B42%2B19%7D%7B5%7D%3D27)
So, step 1 is correct.
2)
The absolute deviation of a value in the dataset is the absolute value of its difference from the mean value:
![\sigma_i = |x_i-\bar x|](https://tex.z-dn.net/?f=%5Csigma_i%20%3D%20%7Cx_i-%5Cbar%20x%7C)
Since here the mean value is
![\bar x=27](https://tex.z-dn.net/?f=%5Cbar%20x%3D27)
Then for each of the values in this dataset, we have:
![\sigma_{1}=|35-27|=8\\\sigma_{2}=|16-27|=11\\\sigma_{3}=|23-27|=4\\\sigma_{4}=|42-27|=15\\\sigma_{5}=|19-27|=8](https://tex.z-dn.net/?f=%5Csigma_%7B1%7D%3D%7C35-27%7C%3D8%5C%5C%5Csigma_%7B2%7D%3D%7C16-27%7C%3D11%5C%5C%5Csigma_%7B3%7D%3D%7C23-27%7C%3D4%5C%5C%5Csigma_%7B4%7D%3D%7C42-27%7C%3D15%5C%5C%5Csigma_%7B5%7D%3D%7C19-27%7C%3D8)
So calculations in step 2 are also correct.
3)
The mean absolute deviation is given by the sum of the absolute deviations for each data divided by the number of values in the dataset.
Therefore in this problem, it is:
![\bar \sigma = \frac{\sum \sigma_i}{N}=\frac{8+11+4+15+8}{5}=9.2](https://tex.z-dn.net/?f=%5Cbar%20%5Csigma%20%3D%20%5Cfrac%7B%5Csum%20%5Csigma_i%7D%7BN%7D%3D%5Cfrac%7B8%2B11%2B4%2B15%2B8%7D%7B5%7D%3D9.2)
While the result reported by Dora is 9.5: therefore, this step is not correct.