We can see from the diagram that the length of the rectangle is 2 lots of the radius of one quarter circle. The width is made up of one radius, therefore the width is half of the length.
This means that the width of the rectangle is 9cm, and the radius of each quarter circle is 9cm.
To find the shaded area, we find the area of the rectangle and subtract from the areas of each circle, which are equal:
A = lw - 1/2(pi x r^2)
A = 9 x 18 - 1/2(81pi)
A = 162 - 81/2 pi
A = 34.8cm (3sf)
Step-by-step explanation:
The answer is option b.
Explanation in the pic.
Need any other maths, feel free!!
The extraneous solution of startroot 4 x 41 endroot = x 5 will be A. -8.
<h3>What is an extraneous solution?</h3>
It should be noted that an extraneous solution simply means a root of a transformed equation which isn't part of the original equation.
✓4x + 41 = x + 5
Square both sides
4x + 41 = x² + 10x + 25
x² + 6x - 16
x(x + 8) - 2(x + 8) = 0
x + 8 = 0
x= 0 + 8 = 8
Learn more about extraneous solution on:
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168cm2
Let r cm be the radius of the balloon, then
<span>2pi(r)=23=>r=23/(2pi) </span>
<span>The surface area= </span>
<span>4pi(r^2)= </span>
<span>4pi[23/2pi)]^2= </span>
<span>(23^2)/pi=168.386 cm^2 </span>
<span>approximately.</span>
The answer is 2. hope thishelps
