Answer:
-18
Remember PEMDAS.
Step-by-step explanation:
Answer:

Explanation: For this, it is often best to find the horizontal asymptote, and then take limits as x approaches the vertical asymptote and the end behaviours.
Well, we know there will be a horizontal asymptote at y = 0, because as x approaches infinite and negative infinite, the graph will shrink down closer and closer to 0, but never touch it. We call this a horizontal asymptote.
So we know that there is a restriction on the y-axis.
Now, since we know the end behaviours, let's find the asymptotic behaviours.
As x approaches the asymptote of 7⁻, then y would be diverging out to negative infinite.
As x approaches the asymptote at 7⁺, then y would be diverging out to negative infinite.
So, our range would be:
Assumption:
<em>Something is missing in question. If we see deeply it is apparent that there is some issue with option b i.e. </em><em>B) 8 − 4x 10 = 4 + 2x </em><em>we assume that the questioner want to type </em><em>B) 8-4x^10 = 4 + 2x.</em>
Answer:
The correct answer is <em> </em><em>B) 8-4x^10 = 4 + 2x.</em>
Step-by-step explanation:
All equations given is the question can be solve easily to determine the value of x. However if we solve equation mentioned in option b we cannot get single answer easily.
For example value of x in eq given in option A
15x + 123 = 5x+4
1oX = -119
X = -119/10
Answer:
1) n=-12
2) y=-8
3) x= 1/30
Step-by-step explanation:
1) 7+n=-5
7+n-7=-5-7
n=-12
2) 18=-3y-6
-3y-6=18
-3y-6+6=18+6
-3y=24
-3y/-3 = 24/-3
y= -8
3) 3/5x=18
3/15 X 5x= 18 X 5x
3=90x
90x/90= 3/90
x= 1/30