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3 years ago

Given functions f(x) and g(x) below, find f(x) + g(x) and simplify."

Mathematics

1 answer:

melisa1 [442]3 years ago

5 0

Answer:

3x-2

Step-by-step explanation:

f(x) + g(x)

(2x+1)+(x-3)

2x+1+x-3

3x+1-3

3x-2

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Whats 913 divide by 29 show your work

Morgarella [4.7K]

913 decided by 29 is 31.4827

4 0

3 years ago

If a + b + c = − 2 a+b+c=−2a, plus, b, plus, c, equals, minus, 2 and x + y = 1 0 x+y=10x, plus, y, equals, 10, what is − 9 a + 2

WARRIOR [948]

Sorry but your question makes no sense as posted. Please, post exactly as written in your textbook.

8 0

3 years ago

Sammy can roll a bowling ball at a rate of 5 miles in 30 seconds. How fast can he

IgorLugansk [536]

Answer:

600 mph

Step-by-step explanation:

Given that,

Distance covered by ball, d = 5 miles

Time taken, t = 30 seconds

1 second = (1/3600) hour

Speed = distance/time

$v=\dfrac{5\ \text{miles}}{30\times \dfrac{1}{3600}\ \text{hour}}\\\\v=600\ mph$

So, the speed of the ball is 600 mph.

3 0

4 years ago

A manufacturer of bicycles has determined that 550 bikes per month will be sold at a price of $250. At a price of $150, it is es

iogann1982 [59]

750 bikes would be sold for $350

Let x represent the number of bikes sold per month and y represent the price.

550 bikes are sold at a price of $250, this can be represented by (550, 250). Also, 750 bikes is sold at a price of $150, hence it is represented by (750, 150)

A linear function is represented by:

y = mx + b

m is the slope, b is the y intercept.

Therefore the function is:

$y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)\\\\y-250=\frac{150-250}{750-550} (x-550)\\\\y=\frac{1}{2}x-25$

The number of bikes sold for $350 is:

350 = (1/2)x - 25

x = 750

Therefore 750 bikes would be sold for $350

Find out more at: brainly.com/question/13911928

3 0

3 years ago

Show that if u+v and u-v are orthognal, then the vectors u and v must have the same length.

pashok25 [27]

Answer with Step-by-step explanation:

We are given that

u+ v and u-v are orthogonal

We have to prove that u and v must have the same length.

When two vector a and b are orthogonal then

$a\cdot b=0$

By using the property

$(u+v)\cdot (u-v)=0$

We know that

$(a+b)\cdot (a-b)=\mid a\mid^2-\mid b\mid^2$

$\mid u\mid ^2-\mid v\mid^2=0$

$\mid u\mid^2=\mid v\mid^2$

Magnitude is always positive

When power of base on both sides are equal then base will be equal

Therefore,

$\mid u\mid=\mid v\mid$

Hence, the length of vectors u and v must have the same length.

5 0

4 years ago