Answer:
Step-by-step explanation:
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Need a picture to tell for sure, sorry
Answer: There are 12 white and blue cars more than silver and red cars
Number of white cars: n1=25
Number of blue cars: n2=17
Number of white and blue cars: n3=n1+n2=25+17→n3=42
Number of silver cars: n4=21
Number of red cars: n5=9
Number of silver and red cars: n6=n4+n5=21+9→n6=30
How many more white and blue cars are there than silver and red cars?
n=?
n=n3-n6=42-30→n=12
Answer: There are 12 white and blue cars more than silver and red cars.
The intersection of the steps is just a fancy way of asking wi\hich numbers are in both equations so lets look and see :)
The 1st = 0...1...5...7...8
The 2nd =0........5...7........9
Answer = D {0, 5, 7}
Hope this helps have any questions let me know :)
Answer:
a 166 67/100
b 20 1/4
c 829 77/100
d 664 47/50
e 208 4/25
Step-by-step explanation:
you need to find the common denominator (the number on the bottom) so for the first one when can 10 = 100 if you multiply 10 x 10 you get 100 so multiply the entire fraction by 10 and you will get 10/100 so the equation would be 381 10/100 - 214 43/100 which equals 166 67/100 then just do the same thing for the rest of them
