The Answer is F.
20min - 30min is -10 so you can take it out of 8h which will leave you with 7h and 50 minutes then
7h and 50 min minus 10 h is -3 h and 50 minutes take it out of the 7 day’s which leaves you with 6days and 24 h minus 3 h that it 6days and 21 h and 50 minutes in total and minus the ram aiming 4 days which will be
2days 21 hours 50 minutes and that gives you the answer F
Answer:
-log2
Step-by-step explanation:
log4 - log8 = log2² - log2³
= 2log2 - 3log2
= (2 - 3)×log2
= (-1)×log(2)
= -log2
Answer:
The number of bracelets with she start are 48.
Step-by-step explanation:
Given:
Julia was recently given 9 bracelets. She plans to give 1/3 of her bracelets. She will be left with 23.
Now, we need to find with how many did she start.
Let the bracelets with she start be .
She plans to give = .
According to question:
On solving the equation:
<em>Multiplying both sides by 3 we get:</em>
<em>Adding both sides by 27 and then dividing by 2 we get:</em>
Therefore, the number of bracelets with she start are 48.
Answer:1.69*10^12 J
Step-by-step explanation:
From figure above, using triangle ratio
485/755.5=y/l. Cross multiplying 485l=755.5y Divide via 485) hence l= 755.5y/485
Consider a slice volume Vslice= (755.5y/485)^2∆y; recall density =150lb/ft^3
Force slice = 150*755.5^2.y^2.∆y/485^2
From figure 2 in the attachment work done for elementary sclice
Wslice= 150.755.5^2.y^2.∆y.(485-y)/485^2
= (150*755.5^2*y^2)(485-y)∆y/485
To calculate the total work we integrate from y=0 to y= 485
Ie W=[ integral of 150*755.5^2 *y^2(485-y)dy/485] at y=0 and y= 485
Integrating the above
W= 150*755.5^2/485[485*y^3/3-y^4/4] at y= 0 and y=485
W= 150*755.5^2/485(485*485^3/3-484^4/4)-(485.0^3/3-0^4/4)
Work done 1.69*10^12joules