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nikitadnepr [17]
4 years ago
8

Worksheet 2.3 writing formulas

Chemistry
1 answer:
kogti [31]4 years ago
5 0

Where's the question(s)?

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How many cobalt atoms are in 345 g of cobalt
lilavasa [31]

Answer:

\boxed {\boxed {\sf About \ 3.53 \ *10^{24}atoms \ Co}}

Explanation:

To convert from grams to atoms:

  1. Convert grams to moles
  2. Convert moles to grams

1. <u>Convert grams to moles</u>

First, find the molar mass of cobalt using the Periodic Table of Elements.

  • Cobalt (Co): 58.93319 g/mol

Next, use this mass as a ratio or fraction.

\frac{58.93319 \ g\ Co}{1 \ mol \ Co}

Multiply the mass of the given sample (345 grams) by this ratio.

345 \ g \ Co *\frac{58.93319 \ g\ Co}{1 \ mol \ Co}

Flip the fraction so the grams of Cobalt will cancel each other out when multiplying.

345 \ g \ Co *\frac{1 \ mol \ Co}{58.93319 \ g\ Co}

345 \  *\frac{1 \ mol \ Co}{58.93319 }

\frac{345 \ mol \ Co}{58.93319 } =5.854086636 \ mol \ Co

2. <u>Convert moles to atoms</u>

Use Avogadro's Number, which tells us the number of units (in this case atoms) in 1 mole.

  • 6.022 *10^{23} \ atoms/mol

Use this number as a ratio or fraction.

\frac{6.022 * 10^{23} \ atoms \ Co}{1 \ mol \ Co}}

Multiply this ratio by the number of moles we found.

5.854086636 \ mol \ Co*\frac{6.022 * 10^{23 }\ atoms \ Co}{1 \ mol \ Co}}

The moles of Cobalt will cancel.

5.854086636 \ *\frac{6.022 * 10^{23 }\ atoms \ Co}{1 }}

5.854086636 \ *{6.022 * 10^{23 }\ atoms \ Co}

3.52533097*10^{24} \ atoms \ Co

3.<u>Round</u>

The original measurement of 345 has 3 significant figures (3, 4, and 5). We must round to 3 sig figs, which is the hundredth place for this measurement.

3.52533097*10^{24} \ atoms \ Co

The 5 in the thousandth place tells us to round the 2 to a 3.

3.53 \ *10^{24}atoms \ Co

There are about <u>3.53*10²⁴ atoms of cobalt in 345 grams.</u>

6 0
3 years ago
Sodium hydroxide is used extensively in acid-base titrations because it is a strong, inexpensive base. A sodium hydroxide soluti
NeX [460]

Answer: The molarity of the base solution is 0.22 M.

Explanation:

According to the neutralization law,

n_1M_1V_1=n_2M_2V_2

where,

M_1 = molarity of HCl solution = 0.1994 M

V_1 = volume of HCl solution = 38.87 ml

M_2 = molarity of NaOH solution = ?

V_2 = volume of NaOH solution = Final reading - Initial reading = 36.18 - 1.16 = 35.02 ml

n_1 = valency of HCl = 1

n_2 = valency of NaOH = 1

1\times 0.1994\times 38.87=1\times M_2\times 35.02

M_2=0.22M

Therefore, the molarity of the base solution is 0.22 M.

8 0
4 years ago
Read 2 more answers
Which of the following would have the smallest ionization energy?<br> S<br> Р<br> K<br> Ca
goldenfox [79]

Answer:

Ca

Explanation:

Ionization energy decreases from top to bottom and increases from left to right on the periodic table

4 0
3 years ago
What is a light-year?
lara [203]
I think it is B the distance light travels from the sun to the earth 
4 0
3 years ago
Read 2 more answers
1. Determine the number of atoms in 4.64 g gold.
liubo4ka [24]

Answer:

The answer to your question is below

Explanation:

1.-

a) Look for the mass number of Gold in the periodic table

Mass number = 197 g

Use proportions to answer this question

                          197 g of gold ------------- 6.023 x 10 ²³ atoms

                            4.64 g of gold ----------  x

                            x = (4.64 x 6.023 x 10²³) / 197

                           x = 1.42 x 10²² atoms

2.- mass of 4.12 x 10²⁴ molecules of glucose

Molecular mass = (6 x 12) + (12 X 1) + (6 x 16)

                          = 72 + 12 + 96

                          = 180 g

             180 g of glucose ------------------- 6.023 x 10 ²³ molecules

                x                        -------------------  4.12 x 10 ²⁴ molecules

                x = (4.12 x 10²⁴ x 180) / 6.023 x 10²³

               x = 1231.3 g of glucose                  

4 0
3 years ago
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