Considering the reaction stoichiometry and Avogadro's Number, the mass of barium chloride produced is 21.6 grams.
<h2>Balanced reaction</h2>
The balanced reaction is
2 HCl + Ba → BaCl₂ + H₂
<h2>Moles of HCl that react</h2>
Avogadro's Number is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023×10²³ particles per mole. Avogadro's number applies to any substance.
Then you can apply the following rule of three: if 6.023×10²³ molecules are contained in 1 mole of HCl, then 1.25×10²³ molecules are contained in how many moles of HCl?
amount of moles of HCl= (1.25×10²³ molecules × 1 mole)÷ 6.023×10²³ atoms
<u><em>amount of moles of HCl= 0.2075 moles</em></u>
Then, 0.2075 moles of HCl react.
<h2>Reaction stoichiometry</h2>
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
HCl: 2 moles
Ba: 1 mole
BaCl₂: 1 mole
H₂: 1 mole
<h2>Mass of barium chloride produced</h2>
Then you can apply the following rule of three: if by stoichiometry 2 moles of HCl produce 1 mole of BaCl₂, 0.2075 moles of HCl will produce how many moles of BaCl₂?
<u><em>amount of moles of BaCl₂= 0.10375 moles</em></u>
Being the molar mass of BaCl₂ 208.24 g/mole, then the mass of barium chloride produced is calculated as:
Finally, the mass of barium chloride produced is 21.6 grams.
The doubling the amount will change the gibbs free energy as it is an extensive property which depends upon the the amount of the substance
However as asked in question the DeltaG has unit of kcal /mol
So we have already defined the amount of substance to be one mole this means the value per mole will be same irrespective of the amount taken as we are reporting it for a fixed one mole of a substance