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Reptile [31]
3 years ago
9

Cellular respiration occurs within the ________ of a cell. nucleus vacuoles cytoplasm mitochondrion win:

Chemistry
1 answer:
Cerrena [4.2K]3 years ago
7 0
The reaction begins in the cytoplasm but It cellular respiration occurs within the mitochondria.
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Why is there a difference in the conductivity of pure solid NaC1 and of the 1.0 M NaC1 soulution
Basile [38]
That would be cause part of the sodium is pure and that means it still kind of has it properties when it was an element and that its i think.
7 0
4 years ago
Question 2 (5 points)
blagie [28]

The water in Glass A is cooler than the water in Glass B; therefore, the particles in Glass A move slower.

Option D

<h3>Chemical Reactions</h3>

Generally,the experiment shows that  glass B temperature is higher than glass temperature A and this is given that observation that the solute dissolves faster in glass B than glass A.

Therefore,The water in Glass A is cooler than the water in Glass B; therefore, the particles in Glass A move slower.

For more information on Temperature

brainly.com/question/13439286

5 0
2 years ago
Uranium-234 is unstable and undergoes two subsequent alpha emissions. What is the resulting nuclide from this transformation?
MArishka [77]

Answer:Radium

Explanation:

The nuclear reaction involving two alpha emissions of 234 U is shown in the diagram. This leads to the formation of a 226Ra nucleus.

4 0
3 years ago
Which pH indicates a substance that is more acidic than a substance with a pH of 4
dexar [7]
Anything with a pH level of 3, 2, or 1.
8 0
4 years ago
A 5.00 L sample of air at 0 C is warmed to 100.0 C. What is the new volume of the air? First, identify V1.
Paladinen [302]

Answer : The new volume of the air is, 6.83 L

Explanation :

Charles' Law : It states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

\frac{V_1}{T_1}=\frac{V_2}{T_2}

where,

V_1\text{ and }T_1 are the initial volume and temperature of the gas.

V_2\text{ and }T_2 are the final volume and temperature of the gas.

We are given:

V_1=5.00L\\T_1=0^oC=(0+273)K=273K\\V_2=?\\T_2=100^oC=(100+273)K=373K

Putting values in above equation, we get:

\frac{5.00L}{273K}=\frac{V_2}{373K}\\\\V_2=6.83L

Therefore, the new volume of the air is, 6.83 L

6 0
4 years ago
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