Answer:
What is the mass of solute, in grams, in 250.00 mL of a 0.0125 M solution of KMnO4? Moles KMnO4 = M × V = 0.0125 M × 0.250 L = 3.13 × 10-3 mol KMnO4 grams KMnO4 = 3.13 × 10-3 mol KMnO4 × ( 158.03 g KMnO4/1 mol KMnO4) = 0.495 g 4.
The formula of aluminum sulfate is Al₂(SO₄)₃
Hence, 1 mole of Al₂(SO₄)₃ has 2 moles of Al, 3 moles of S and (4 x 3) or 12 moles of O
9 moles of Al₂(SO₄)₃ x (2 moles of Al/1 mole of Al₂(SO₄)₃) = 18 moles of Al
9 moles of Al₂(SO₄)₃ x (3 moles of S/1 mole of Al₂(SO₄)₃) = 27 moles of S
9 moles of Al₂(SO₄)₃ x (12 moles of O/1 mole of Al₂(SO₄)₃) = 108 moles of O
The number of moles of Al, S, and O atoms are 18, 27 and 108.
Depends on the gas and grams of solute. If you were able to give me a gas i would be able to help you but i cannot without the gas or chemical makeup.
