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Sloan [31]
3 years ago
7

Please help :(( look at the picture! 8 points !

Mathematics
1 answer:
pochemuha3 years ago
7 0

Answer:

the picture isnt loading can you type the question instead?

Step-by-step explanation:

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A basket weighs 12 oz. A watermelon weighing 7 lb 9 oz is added to the basket. What is the total weight of the basket and waterm
SSSSS [86.1K]
7 lbs is 112 ounces. 112 plus 9 is 121. 121 plus 12 is 133. The total weight of the basket and the watermelon is 133 ounces. I'm not sure how you need the answer so I'll leave it in a couple different forms.

Ounces- 133
Pounds- 8.312 (rounds to the nearest tenth, 8.3)
Pounds and ounces- 8 pounds and 5 ounces
3 0
3 years ago
If you wont bairlest help plz
natta225 [31]

Answer:

C D and E

Step-by-step explanation: Give me "bairlest"

4 0
3 years ago
Read 2 more answers
A 2,000-foot-long fence will be used to enclose a rectangular field that is three times as long as it is wide. What is the lengt
BartSMP [9]
I think it's another trick question and the answer is 2000.
4 0
3 years ago
Help again for the last time ;-;
lys-0071 [83]

Answer:

1) Star: (-5,9) 2) Lightning (0,8)

3) Circle: (4,-7) 4) Heart (-3,-8)

5) Cross (6,9) 6) Triangle (0,6)

7) Moon (-4,9) 8) Square (-4,6)

9) Diamond (-1,-4) 10) Music Note (8,1)

Step-by-step explanation:

The way that I solved this was I first set up (x,y). You must find the placement of the x-axis or the horizontal line. Then you find the 7-axis or the vertical line. For example, with the star, the shape is 5 to the left which is -5 and then goes 9 lines upward.

7 0
3 years ago
wo point charges lie on the $x$ axis. A charge of +6.24 $\mu C$ is at the origin, and a charge of -9.55 $\mu C$ is at $x$ = 12.0
Andreyy89

Answer:

E_n=34,467,075.42\ N/C

Step-by-step explanation:

<u>Electric Field</u>

The electric field produced by a point charge Q at a distance d is given by

\displaystyle E=K\cdot \frac{Q}{d^2}

Where

K = 9\cdot 10^9\ Nw.m^2/c^2

The net electric field is the vector addition of the individual electric fields produced by each charge. The direction is given by the rule: If the charge is positive, the electric field points outward, if negative, it points inward.

Let's calculate the electric fields of each charge at the given point. The first charge q_1=+6.24\mu C=6.24\cdot 10^{-6}C is at the origin. We'll calculate its electric field at the point x=-3.85 cm. The distance between the charge and the point is d=3.85 cm = 0.0385 m, and the electric field points to the left:

\displaystyle E_1=9\cdot 10^9\cdot \frac{6.24\cdot 10^{-6}}{0.0385^2}

E_1=37,888,345.42\ N/C

Similarly, for q_2=-9.55\mu C=-9.55\cdot 10^{-6}C, the distance to the point is 12 cm + 3.85 cm = 15.85 cm = 0.1585 m. The electric field points to the right:

\displaystyle E_2=9\cdot 10^9\cdot \frac{9.55\cdot 10^{-6}}{0.1585^2}

E_2=3,421,270\ N/C

Since E1 and E2 are opposite, the net field is the subtraction of both

E_n=37,888,345.42\ N/C-3,421,270\ N/C

\boxed{E_n=34,467,075.42\ N/C}

6 0
4 years ago
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